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3,400	acac7cb1-6ddd-11ea-ae62-ccda262736ce	https://socratic.org/questions/what-is-the-molality-of-a-solution-in-which-2-3-g-o-2-gas-dissolved-in-355-g-of-	0.20 m	start physical_unit 6 6 molality m qc_end physical_unit 11 12 9 10 mass qc_end physical_unit 18 18 15 16 mass qc_end end	[{"type":"physical unit","value":"Molality [OF] the solution [IN] m"}]	[{"type":"physical unit","value":"0.20 m"}]	[{"type":"physical unit","value":"Mass [OF] O2 gas [=] \\pu{2.3 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{355 g }"}]	<h1 class="questionTitle" itemprop="name">What is the molality of a solution in which 2.3 g #O_2# gas dissolved in 355 g of water?</h1>	null	0.20 m	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a> can be found using the equation below:</p> <p><img alt="study.com" src="https://useruploads.socratic.org/AvAZClfYSgiZ06ET8EfA_molality_formula.png"/> </p> <p>What you want to do now is determine what the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute and solvent are.</a> A <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is dissolved in the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the solute is the "minor component in a solution."The solvent is usually water or it is the substance that you have more of. In our case, the solute is <mathjax>#O_2#</mathjax> and the solvent is water.</p> <p>As we can see from the equation, the solute and solvent have the wrong units. Let's start by converting grams of <mathjax>#O_2#</mathjax> to moles of <mathjax>#O_2#</mathjax>. We do this by using the molar mass of <mathjax>#O_2#</mathjax> as a conversion factor.</p> <p><mathjax>#2.3cancel"g"O_2xx (1mol O_2)/(32.00cancel"g")= 0.0719 mol O_2#</mathjax></p> <p>Now we need kg of solvent instead of the grams that we're given. Let's use this relationship: <br/> <img alt="www.internetdict.com" src="https://useruploads.socratic.org/I2wrA0DSIO1UybNyFnRg_how-many-grams-in-a-kilogram_3.jpg"/> </p> <p><mathjax>#355cancel"g" H_2O xx (1kg)/(1000cancel"g") = .355kg H_2O#</mathjax></p> <p>Now all we do is plug the values into the equation like this:</p> <p><mathjax>#molality = (0.0719 mol)/(0.355kg)#</mathjax> = <mathjax>#0.20 m#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.20m#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a> can be found using the equation below:</p> <p><img alt="study.com" src="https://useruploads.socratic.org/AvAZClfYSgiZ06ET8EfA_molality_formula.png"/> </p> <p>What you want to do now is determine what the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute and solvent are.</a> A <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is dissolved in the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the solute is the "minor component in a solution."The solvent is usually water or it is the substance that you have more of. In our case, the solute is <mathjax>#O_2#</mathjax> and the solvent is water.</p> <p>As we can see from the equation, the solute and solvent have the wrong units. Let's start by converting grams of <mathjax>#O_2#</mathjax> to moles of <mathjax>#O_2#</mathjax>. We do this by using the molar mass of <mathjax>#O_2#</mathjax> as a conversion factor.</p> <p><mathjax>#2.3cancel"g"O_2xx (1mol O_2)/(32.00cancel"g")= 0.0719 mol O_2#</mathjax></p> <p>Now we need kg of solvent instead of the grams that we're given. Let's use this relationship: <br/> <img alt="www.internetdict.com" src="https://useruploads.socratic.org/I2wrA0DSIO1UybNyFnRg_how-many-grams-in-a-kilogram_3.jpg"/> </p> <p><mathjax>#355cancel"g" H_2O xx (1kg)/(1000cancel"g") = .355kg H_2O#</mathjax></p> <p>Now all we do is plug the values into the equation like this:</p> <p><mathjax>#molality = (0.0719 mol)/(0.355kg)#</mathjax> = <mathjax>#0.20 m#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molality of a solution in which 2.3 g #O_2# gas dissolved in 355 g of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276127" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-11T01:13:42" itemprop="dateCreated"> Jun 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.20m#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a> can be found using the equation below:</p> <p><img alt="study.com" src="https://useruploads.socratic.org/AvAZClfYSgiZ06ET8EfA_molality_formula.png"/> </p> <p>What you want to do now is determine what the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute and solvent are.</a> A <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is dissolved in the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the solute is the "minor component in a solution."The solvent is usually water or it is the substance that you have more of. In our case, the solute is <mathjax>#O_2#</mathjax> and the solvent is water.</p> <p>As we can see from the equation, the solute and solvent have the wrong units. Let's start by converting grams of <mathjax>#O_2#</mathjax> to moles of <mathjax>#O_2#</mathjax>. We do this by using the molar mass of <mathjax>#O_2#</mathjax> as a conversion factor.</p> <p><mathjax>#2.3cancel"g"O_2xx (1mol O_2)/(32.00cancel"g")= 0.0719 mol O_2#</mathjax></p> <p>Now we need kg of solvent instead of the grams that we're given. Let's use this relationship: <br/> <img alt="www.internetdict.com" src="https://useruploads.socratic.org/I2wrA0DSIO1UybNyFnRg_how-many-grams-in-a-kilogram_3.jpg"/> </p> <p><mathjax>#355cancel"g" H_2O xx (1kg)/(1000cancel"g") = .355kg H_2O#</mathjax></p> <p>Now all we do is plug the values into the equation like this:</p> <p><mathjax>#molality = (0.0719 mol)/(0.355kg)#</mathjax> = <mathjax>#0.20 m#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276127" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molality-be"> How high can molality be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molality-from-molarity"> How do you calculate molality from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-used-for-colligative-properties"> Why is molality used for colligative properties? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-independent-of-temperature"> Why is molality independent of temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-molality-when-75-0-grams-of-mgcl2-is-dissolved-in-500-0-"> How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/49-8-grams-of-ki-is-dissolved-in-1-00-kg-of-solvent-what-is-the-molality"> 49.8 grams of KI is dissolved in 1.00 kg of solvent. What is the molality? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/58-44-grams-of-nacl-and-you-dissolved-it-in-exactly-2-00-kg-of-pure-water-the-so"> 58.44 grams of NaCl and you dissolved it in exactly 2.00 kg of pure water (the solvent). What... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-0-75-mol-is-dissolved-in-2-50-l-of-solvent"> What is the molality when 0.75 mol is dissolved in 2.50 L of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-48-0-ml-of-6-00-m-h2so4-are-diluted-into-0-250-l"> What is the molality when 48.0 mL of 6.00 M H2SO4 are diluted into 0.250 L? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molality"> See all questions in Molality </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6032 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molality of a solution in which 2.3 g #O_2# gas dissolved in 355 g of water?	null
3,401	ab441ad3-6ddd-11ea-b118-ccda262736ce	https://socratic.org/questions/59a97c767c01495a82ea0727	1.85 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 10 11 6 7 mass qc_end end	[{"type":"physical unit","value":"Number [OF] bromine atoms"}]	[{"type":"physical unit","value":"1.85 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] bromine molecules [=] \\pu{246.1 g}"}]	<h1 class="questionTitle" itemprop="name">How many bromine atoms in a #246.1*g# mass of bromine molecules?</h1>	null	1.85 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You simply have to know that the bromine molecule is binuclear under standard conditions, i.e. <mathjax>#Br_2#</mathjax>, and the rest of halogens are also <mathjax>#X_2#</mathjax>.</p> <p>And so we gots <mathjax>#1.54mol#</mathjax> with respect to molecular <mathjax>#Br_2#</mathjax>, i.e. <mathjax>#3.08mol#</mathjax> bromine atoms. Are you with me?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3.08mol#</mathjax> <mathjax>#"bromine atoms........"#</mathjax>, i.e. <mathjax>#3.08molxx6.022xx10^23mol^-1#</mathjax> individual bromine atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You simply have to know that the bromine molecule is binuclear under standard conditions, i.e. <mathjax>#Br_2#</mathjax>, and the rest of halogens are also <mathjax>#X_2#</mathjax>.</p> <p>And so we gots <mathjax>#1.54mol#</mathjax> with respect to molecular <mathjax>#Br_2#</mathjax>, i.e. <mathjax>#3.08*mol#</mathjax> bromine atoms. Are you with me?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many bromine atoms in a #246.1g# mass of bromine molecules?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="470590" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-01T15:31:44" itemprop="dateCreated"> Sep 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3.08mol#</mathjax> <mathjax>#"bromine atoms........"#</mathjax>, i.e. <mathjax>#3.08molxx6.022xx10^23mol^-1#</mathjax> individual bromine atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You simply have to know that the bromine molecule is binuclear under standard conditions, i.e. <mathjax>#Br_2#</mathjax>, and the rest of halogens are also <mathjax>#X_2#</mathjax>.</p> <p>And so we gots <mathjax>#1.54mol#</mathjax> with respect to molecular <mathjax>#Br_2#</mathjax>, i.e. <mathjax>#3.08mol#</mathjax> bromine atoms. Are you with me?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/470590" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3230 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many bromine atoms in a #246.1*g# mass of bromine molecules?	null
3,402	a9ed13c8-6ddd-11ea-a0bb-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-balanced-chemical-equation-depicting-the-formation-of-one-mol	2 C(s) + 3 H2(g) + 1/2 O2(g) -> C2H5OH(l)	start chemical_equation qc_end physical_unit 15 15 12 13 mole qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 C(s) + 3 H2(g) + 1/2 O2(g) -> C2H5OH(l)"}]	[{"type":"physical unit","value":"Mole [OF] C2H5OH(l) [=] \\pu{1 mole}"},{"type":"other","value":"Standard states."}]	<h1 class="questionTitle" itemprop="name">How do you write a balanced chemical equation depicting the formation of one mole of #C_2H_5OH(l)# from its elements in their standard states?</h1>	null	2 C(s) + 3 H2(g) + 1/2 O2(g) -> C2H5OH(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, does this depict the formation of one mole of ethyl alcohol from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states under standard conditions.........?</p> <p>Now of course, we could not perform this reaction on a laboratory bench-top. There are easier ways to make ethyl alcohol (which are?). Nevertheless, there exist enuff data to allow us to estimate the thermodynamic change when this reaction is (conceptually!) performed. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C(s) + 3H_2(g) + 1/2O_2(g) rarr C_2H_5OH(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, does this depict the formation of one mole of ethyl alcohol from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states under standard conditions.........?</p> <p>Now of course, we could not perform this reaction on a laboratory bench-top. There are easier ways to make ethyl alcohol (which are?). Nevertheless, there exist enuff data to allow us to estimate the thermodynamic change when this reaction is (conceptually!) performed. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write a balanced chemical equation depicting the formation of one mole of #C_2H_5OH(l)# from its elements in their standard states?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386205" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T05:49:55" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C(s) + 3H_2(g) + 1/2O_2(g) rarr C_2H_5OH(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, does this depict the formation of one mole of ethyl alcohol from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states under standard conditions.........?</p> <p>Now of course, we could not perform this reaction on a laboratory bench-top. There are easier ways to make ethyl alcohol (which are?). Nevertheless, there exist enuff data to allow us to estimate the thermodynamic change when this reaction is (conceptually!) performed. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386205" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5221 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write a balanced chemical equation depicting the formation of one mole of #C_2H_5OH(l)# from its elements in their standard states?	null
3,403	ac0fa0dc-6ddd-11ea-9c68-ccda262736ce	https://socratic.org/questions/the-titration-of-an-impure-sample-of-khp-found-that-36-0-ml-0-100-m-naoh-was-req	96.1%	start physical_unit 30 33 percent none qc_end physical_unit 14 14 12 13 molarity qc_end c_other OTHER qc_end physical_unit 5 7 21 22 mass qc_end end	[{"type":"physical unit","value":"Percentage [OF] KHP in this sample"}]	[{"type":"physical unit","value":"96.1%"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{36.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.100 M}"},{"type":"other","value":"React completely."},{"type":"physical unit","value":"Mass [OF] KHP sample [=] \\pu{0.765 g}"}]	<h1 class="questionTitle" itemprop="name">The titration of an impure sample of KHP found that 36.0 mL 0.100 M NaOH was required to react completely with 0.765 g of sample. What is the percentage of KHP in this sample?</h1>	null	96.1%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction with <mathjax>#"NaOH"#</mathjax> is</p> <p><mathjax>#"KHC"_8"H"_4"O"_4 + "NaOH" → "KNaC"_8"H"_4"O"_4 + "H"_2"O"#</mathjax><br/> <mathjax>#color(white)(mll)"KHP"color(white)(mll) + "NaOH" → color(white)(mll)"KNaP" color(white)(ml)+ "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Let's start by calculating the moles of <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of NaOH" = 0.0360 color(red)(cancel(color(black)("L NaOH"))) × "0.100 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.003 60 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p>Now we can calculate the moles of <mathjax>#"KHP"#</mathjax> neutralized by the <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of KHP" = 0.003 60 color(red)(cancel(color(black)("mol NaOH"))) × "1 mol KHP"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.003 60 mol KHP"#</mathjax> </p> <blockquote></blockquote> <p>And now we can calculate the mass of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Mass" = "0.003 60" color(red)(cancel(color(black)("mol KHP"))) × "204.22 g KHP"/(1 color(red)(cancel(color(black)("mol KHP")))) = "0.7352 g KHP"#</mathjax></p> <blockquote></blockquote> <p>Finally, we calculate the purity of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Purity" = "mass of pure KHP"/"mass of impure KHP" × 100 % = (0.7352 color(red)(cancel(color(black)("g"))))/(0.765 color(red)(cancel(color(black)("g")))) × 100 % = 96.1 %#</mathjax></p> <p>The <mathjax>#"KHP"#</mathjax> is 96.1 % pure.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"KHP"#</mathjax> is 96.1 % pure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction with <mathjax>#"NaOH"#</mathjax> is</p> <p><mathjax>#"KHC"_8"H"_4"O"_4 + "NaOH" → "KNaC"_8"H"_4"O"_4 + "H"_2"O"#</mathjax><br/> <mathjax>#color(white)(mll)"KHP"color(white)(mll) + "NaOH" → color(white)(mll)"KNaP" color(white)(ml)+ "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Let's start by calculating the moles of <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of NaOH" = 0.0360 color(red)(cancel(color(black)("L NaOH"))) × "0.100 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.003 60 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p>Now we can calculate the moles of <mathjax>#"KHP"#</mathjax> neutralized by the <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of KHP" = 0.003 60 color(red)(cancel(color(black)("mol NaOH"))) × "1 mol KHP"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.003 60 mol KHP"#</mathjax> </p> <blockquote></blockquote> <p>And now we can calculate the mass of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Mass" = "0.003 60" color(red)(cancel(color(black)("mol KHP"))) × "204.22 g KHP"/(1 color(red)(cancel(color(black)("mol KHP")))) = "0.7352 g KHP"#</mathjax></p> <blockquote></blockquote> <p>Finally, we calculate the purity of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Purity" = "mass of pure KHP"/"mass of impure KHP" × 100 % = (0.7352 color(red)(cancel(color(black)("g"))))/(0.765 color(red)(cancel(color(black)("g")))) × 100 % = 96.1 %#</mathjax></p> <p>The <mathjax>#"KHP"#</mathjax> is 96.1 % pure.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The titration of an impure sample of KHP found that 36.0 mL 0.100 M NaOH was required to react completely with 0.765 g of sample. What is the percentage of KHP in this sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266196" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-15T23:48:09" itemprop="dateCreated"> May 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"KHP"#</mathjax> is 96.1 % pure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction with <mathjax>#"NaOH"#</mathjax> is</p> <p><mathjax>#"KHC"_8"H"_4"O"_4 + "NaOH" → "KNaC"_8"H"_4"O"_4 + "H"_2"O"#</mathjax><br/> <mathjax>#color(white)(mll)"KHP"color(white)(mll) + "NaOH" → color(white)(mll)"KNaP" color(white)(ml)+ "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Let's start by calculating the moles of <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of NaOH" = 0.0360 color(red)(cancel(color(black)("L NaOH"))) × "0.100 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.003 60 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p>Now we can calculate the moles of <mathjax>#"KHP"#</mathjax> neutralized by the <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Moles of KHP" = 0.003 60 color(red)(cancel(color(black)("mol NaOH"))) × "1 mol KHP"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.003 60 mol KHP"#</mathjax> </p> <blockquote></blockquote> <p>And now we can calculate the mass of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Mass" = "0.003 60" color(red)(cancel(color(black)("mol KHP"))) × "204.22 g KHP"/(1 color(red)(cancel(color(black)("mol KHP")))) = "0.7352 g KHP"#</mathjax></p> <blockquote></blockquote> <p>Finally, we calculate the purity of the <mathjax>#"KHP"#</mathjax>.</p> <p><mathjax>#"Purity" = "mass of pure KHP"/"mass of impure KHP" × 100 % = (0.7352 color(red)(cancel(color(black)("g"))))/(0.765 color(red)(cancel(color(black)("g")))) × 100 % = 96.1 %#</mathjax></p> <p>The <mathjax>#"KHP"#</mathjax> is 96.1 % pure.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266196" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 39665 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The titration of an impure sample of KHP found that 36.0 mL 0.100 M NaOH was required to react completely with 0.765 g of sample. What is the percentage of KHP in this sample?	null
3,404	acadb54c-6ddd-11ea-b663-ccda262736ce	https://socratic.org/questions/what-is-the-simplest-formula-for-copper-ii-and-nitride	Cu3N2	start chemical_formula qc_end substance 6 7 qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the simplest formula [IN] default"}]	[{"type":"chemical equation","value":"Cu3N2"}]	[{"type":"substance name","value":"Copper (II)"},{"type":"substance name","value":"Nitride"}]	<h1 class="questionTitle" itemprop="name">What is the simplest formula for copper (II) and nitride?</h1>	null	Cu3N2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The easiest way of thinking about the combination of ions is by using the method I recall as being called , "the swap and drop" </p> <p>So we have two ions,</p> <p><mathjax>#Cu^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax></p> <p>now we swap the charge of each and drop, Note that the two ions have to be of opposite charge.</p> <p><mathjax>#Cu_"3"#</mathjax> and <mathjax>#N_2#</mathjax> </p> <p>Now combine,</p> <p><mathjax>#Cu_"3"N_"2"#</mathjax></p> <p>This is the simplest formula.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu_"3"N_"2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The easiest way of thinking about the combination of ions is by using the method I recall as being called , "the swap and drop" </p> <p>So we have two ions,</p> <p><mathjax>#Cu^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax></p> <p>now we swap the charge of each and drop, Note that the two ions have to be of opposite charge.</p> <p><mathjax>#Cu_"3"#</mathjax> and <mathjax>#N_2#</mathjax> </p> <p>Now combine,</p> <p><mathjax>#Cu_"3"N_"2"#</mathjax></p> <p>This is the simplest formula.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the simplest formula for copper (II) and nitride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="327694" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andre-r"><img alt="" class="" src="https://profilepictures.socratic.org/iofl5uEARAa1MKkNS2qp_walking-fingers.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andre-r"> Andre R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-28T04:34:14" itemprop="dateCreated"> Oct 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu_"3"N_"2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The easiest way of thinking about the combination of ions is by using the method I recall as being called , "the swap and drop" </p> <p>So we have two ions,</p> <p><mathjax>#Cu^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax></p> <p>now we swap the charge of each and drop, Note that the two ions have to be of opposite charge.</p> <p><mathjax>#Cu_"3"#</mathjax> and <mathjax>#N_2#</mathjax> </p> <p>Now combine,</p> <p><mathjax>#Cu_"3"N_"2"#</mathjax></p> <p>This is the simplest formula.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/327694" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div 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</li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12583 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the simplest formula for copper (II) and nitride?	null
3,405	aa6efd12-6ddd-11ea-95e8-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-compound-which-has-a-percent-composition-of-4	SO3	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"SO3"}]	[{"type":"physical unit","value":"Percent composition [OF] S in the compound [=] \\pu{40.04%}"},{"type":"physical unit","value":"Percent composition [OF] O in the compound [=] \\pu{59.96%}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound which has a percent composition of 40.04% S and 59.96% O? </h1>	null	SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound.</p> <p>Since the percentages of the elements equal 100%, we can assume we have a 100 g sample, so that the percentage of each element becomes grams. </p> <p><mathjax>#40.04%rArr40.04 "g S"#</mathjax><br/> <mathjax>#59.96%rArr59.96 "g O"#</mathjax></p> <p>First determine the moles of each element by dividing its given mass by its molar mass. The molar mass of an element is its atomic weight (relative atomic mass) on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of S<mathjax>#=#</mathjax><mathjax>#"32.06 g/mol"#</mathjax><br/> Molar mass of O<mathjax>#=#</mathjax><mathjax>#"15.999 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#40.04cancel"g S"xx(1"mol S")/(32.06cancel"g S")="1.249 mol S"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#59.96cancel"g O"xx(1"mol O")/(15.999cancel"g O")="3.748 mol O"#</mathjax></p> <p>Next determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> of each element by dividing the moles of each each element by the smallest number of moles.</p> <p><mathjax>#"S":#</mathjax><mathjax>#(1.249 "mol")/(1.249"mol")=1.000"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(3.748"mol")/(1.249"mol")=3.000"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratios are the lowest whole number ratio of the elements, the empirical formula is <mathjax>#"SO"_3"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"SO"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound.</p> <p>Since the percentages of the elements equal 100%, we can assume we have a 100 g sample, so that the percentage of each element becomes grams. </p> <p><mathjax>#40.04%rArr40.04 "g S"#</mathjax><br/> <mathjax>#59.96%rArr59.96 "g O"#</mathjax></p> <p>First determine the moles of each element by dividing its given mass by its molar mass. The molar mass of an element is its atomic weight (relative atomic mass) on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of S<mathjax>#=#</mathjax><mathjax>#"32.06 g/mol"#</mathjax><br/> Molar mass of O<mathjax>#=#</mathjax><mathjax>#"15.999 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#40.04cancel"g S"xx(1"mol S")/(32.06cancel"g S")="1.249 mol S"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#59.96cancel"g O"xx(1"mol O")/(15.999cancel"g O")="3.748 mol O"#</mathjax></p> <p>Next determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> of each element by dividing the moles of each each element by the smallest number of moles.</p> <p><mathjax>#"S":#</mathjax><mathjax>#(1.249 "mol")/(1.249"mol")=1.000"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(3.748"mol")/(1.249"mol")=3.000"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratios are the lowest whole number ratio of the elements, the empirical formula is <mathjax>#"SO"_3"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound which has a percent composition of 40.04% S and 59.96% O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="199132" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-13T01:22:05" itemprop="dateCreated"> Dec 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"SO"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound.</p> <p>Since the percentages of the elements equal 100%, we can assume we have a 100 g sample, so that the percentage of each element becomes grams. </p> <p><mathjax>#40.04%rArr40.04 "g S"#</mathjax><br/> <mathjax>#59.96%rArr59.96 "g O"#</mathjax></p> <p>First determine the moles of each element by dividing its given mass by its molar mass. The molar mass of an element is its atomic weight (relative atomic mass) on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of S<mathjax>#=#</mathjax><mathjax>#"32.06 g/mol"#</mathjax><br/> Molar mass of O<mathjax>#=#</mathjax><mathjax>#"15.999 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#40.04cancel"g S"xx(1"mol S")/(32.06cancel"g S")="1.249 mol S"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#59.96cancel"g O"xx(1"mol O")/(15.999cancel"g O")="3.748 mol O"#</mathjax></p> <p>Next determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> of each element by dividing the moles of each each element by the smallest number of moles.</p> <p><mathjax>#"S":#</mathjax><mathjax>#(1.249 "mol")/(1.249"mol")=1.000"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(3.748"mol")/(1.249"mol")=3.000"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratios are the lowest whole number ratio of the elements, the empirical formula is <mathjax>#"SO"_3"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/199132" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13480 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a compound which has a percent composition of 40.04% S and 59.96% O?	null
3,406	a9f67d83-6ddd-11ea-9f5e-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-the-binary-compound-nitrogen-dioxide	NO2	start chemical_formula qc_end substance 9 10 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the binary compound [IN] default"}]	[{"type":"chemical equation","value":"NO2"}]	[{"type":"substance name","value":"Nitrogen dioxide"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for the binary compound nitrogen dioxide?</h1>	null	NO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound, nitrogen(IV) oxide, is a radical species as written (it has 17 valence electrons), and participates in the following equilibrium:</p> <p><mathjax>#2NO_2(g) rightleftharpoonsN_2O_4(g)#</mathjax></p> <p>The dimer is colourless, and contains a <mathjax>#N-N#</mathjax> bond presumed to derive from the coupling of the lone electrons on the 2 nitrogen centres; the radical species red brown. </p> <p>Note that the attempt to represent the Lewis structures of these species invariably involves charge separation and FORMAL positive and negative charges on, respectively, nitrogen and oxygen. This is 1st year/2nd year inorganic chemistry rather than A level. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound, nitrogen(IV) oxide, is a radical species as written (it has 17 valence electrons), and participates in the following equilibrium:</p> <p><mathjax>#2NO_2(g) rightleftharpoonsN_2O_4(g)#</mathjax></p> <p>The dimer is colourless, and contains a <mathjax>#N-N#</mathjax> bond presumed to derive from the coupling of the lone electrons on the 2 nitrogen centres; the radical species red brown. </p> <p>Note that the attempt to represent the Lewis structures of these species invariably involves charge separation and FORMAL positive and negative charges on, respectively, nitrogen and oxygen. This is 1st year/2nd year inorganic chemistry rather than A level. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for the binary compound nitrogen dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278017" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-16T12:58:39" itemprop="dateCreated"> Jun 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound, nitrogen(IV) oxide, is a radical species as written (it has 17 valence electrons), and participates in the following equilibrium:</p> <p><mathjax>#2NO_2(g) rightleftharpoonsN_2O_4(g)#</mathjax></p> <p>The dimer is colourless, and contains a <mathjax>#N-N#</mathjax> bond presumed to derive from the coupling of the lone electrons on the 2 nitrogen centres; the radical species red brown. </p> <p>Note that the attempt to represent the Lewis structures of these species invariably involves charge separation and FORMAL positive and negative charges on, respectively, nitrogen and oxygen. This is 1st year/2nd year inorganic chemistry rather than A level. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278017" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-chemical-formula-represents-a-carbohydrate"> What chemical formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-gold"> What is the chemical formula for gold? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-a-diamond"> What is the chemical formula for a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-formulas-for-covalent-compounds"> How do you find formulas for covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-common-mistakes-students-make-with-empirical-forumlas"> What are common mistakes students make with empirical forumlas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-empirical-formulas"> What are empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-empirical-formulas"> What are some examples of empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-naming-a-covalent-bond-between-atoms-how-would-you-write-the-prefix-for-if-"> When naming a covalently-bonded molecule, how would you write the prefix if you had four atoms... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5554 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for the binary compound nitrogen dioxide?	null
3,407	ac11e7ea-6ddd-11ea-b438-ccda262736ce	https://socratic.org/questions/3-00-10-3-mol-ofhbr-are-dissolved-in-water-to-make-16-l-of-solution-what-is-the-	5.33 × 10^(-11) M	start physical_unit 23 23 concentration mol/l qc_end physical_unit 5 5 0 3 mole qc_end substance 9 9 qc_end physical_unit 15 15 12 13 volume qc_end end	[{"type":"physical unit","value":"Concentration [OF] [OH-] [IN] M"}]	[{"type":"physical unit","value":"5.33 × 10^(-11) M"}]	[{"type":"physical unit","value":"Mole [OF] HBr [=] \\pu{3.00 × 10^(-3) mol}"},{"type":"substance name","value":"Water"},{"type":"physical unit","value":"Volume [OF] HBr solution [=] \\pu{16 L}"}]	<h1 class="questionTitle" itemprop="name">#3.00 * 10^-3# mol ofHBr are dissolved in water to make 16 L of solution. What is the concentration of hydroxide ions, [#OH^-#] in this solution?</h1>	null	5.33 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that <mathjax>#10^-14=[HO^-][H_3O^+]#</mathjax> under standard conditions at <mathjax>#298K#</mathjax>......... And should we take <mathjax>#log_10#</mathjax> of BOTH SIDES, we gets......</p> <p><mathjax>#underbrace(log_10(10^-14))_-14=log_10[H_3O^+] + log_10[HO^-]#</mathjax></p> <p>And on rearrangement, <mathjax>#14=underbrace(-log_10[H_3O^+])_(pH)underbrace(-log_10[HO^-])_(pOH)#</mathjax></p> <p>And so our defining relationship, <mathjax>#pH+pOH=14#</mathjax></p> <p>Now.............</p> <p><mathjax>#[H_3O^+]=(3.00xx10^-3mol)/(16L)=1.875xx10^-4molL^-1#</mathjax></p> <p><mathjax>#pH=-log_10(1.875xx10^-4)=-(-3.727)=3.727#</mathjax></p> <p>And thus <mathjax>#pOH=10.27#</mathjax>, and......................</p> <p><mathjax>#[HO^-]=10^(-10.27)=5.33xx10^-11mol*L^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=5.33xx10^-11molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that <mathjax>#10^-14=[HO^-][H_3O^+]#</mathjax> under standard conditions at <mathjax>#298K#</mathjax>......... And should we take <mathjax>#log_10#</mathjax> of BOTH SIDES, we gets......</p> <p><mathjax>#underbrace(log_10(10^-14))_-14=log_10[H_3O^+] + log_10[HO^-]#</mathjax></p> <p>And on rearrangement, <mathjax>#14=underbrace(-log_10[H_3O^+])_(pH)underbrace(-log_10[HO^-])_(pOH)#</mathjax></p> <p>And so our defining relationship, <mathjax>#pH+pOH=14#</mathjax></p> <p>Now.............</p> <p><mathjax>#[H_3O^+]=(3.00xx10^-3mol)/(16L)=1.875xx10^-4molL^-1#</mathjax></p> <p><mathjax>#pH=-log_10(1.875xx10^-4)=-(-3.727)=3.727#</mathjax></p> <p>And thus <mathjax>#pOH=10.27#</mathjax>, and......................</p> <p><mathjax>#[HO^-]=10^(-10.27)=5.33xx10^-11mol*L^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#3.00 * 10^-3# mol ofHBr are dissolved in water to make 16 L of solution. What is the concentration of hydroxide ions, [#OH^-#] in this solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="452038" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-16T00:23:58" itemprop="dateCreated"> Jul 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=5.33xx10^-11molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that <mathjax>#10^-14=[HO^-][H_3O^+]#</mathjax> under standard conditions at <mathjax>#298K#</mathjax>......... And should we take <mathjax>#log_10#</mathjax> of BOTH SIDES, we gets......</p> <p><mathjax>#underbrace(log_10(10^-14))_-14=log_10[H_3O^+] + log_10[HO^-]#</mathjax></p> <p>And on rearrangement, <mathjax>#14=underbrace(-log_10[H_3O^+])_(pH)underbrace(-log_10[HO^-])_(pOH)#</mathjax></p> <p>And so our defining relationship, <mathjax>#pH+pOH=14#</mathjax></p> <p>Now.............</p> <p><mathjax>#[H_3O^+]=(3.00xx10^-3mol)/(16L)=1.875xx10^-4molL^-1#</mathjax></p> <p><mathjax>#pH=-log_10(1.875xx10^-4)=-(-3.727)=3.727#</mathjax></p> <p>And thus <mathjax>#pOH=10.27#</mathjax>, and......................</p> <p><mathjax>#[HO^-]=10^(-10.27)=5.33xx10^-11mol*L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/452038" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-co2"> How do you measure concentration of CO2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-concentration-measure-changes-with-temperature"> What concentration measure changes with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-the-concentration-of-salt-in-water"> How can I measure the concentration of salt in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-concentration-of-a-solution-measured"> How is the concentration of a solution measured? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-concentration-of-electrolyte-affect-an-electrochemical-cell"> How does the concentration of electrolyte affect an electrochemical cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-normality-differ-from-molarity"> How does normality differ from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-of-a-solution-of-10-g-naoh-in-500-g-water"> What is the molality of a solution of 10 g NaOH in 500 g water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-mole-fractions-of-the-components-of-the-solution-formed-when-92-g-g"> What are the mole fractions of the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1690 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#3.00 * 10^-3# mol ofHBr are dissolved in water to make 16 L of solution. What is the concentration of hydroxide ions, [#OH^-#] in this solution?	null
3,408	ac1fd0ae-6ddd-11ea-934e-ccda262736ce	https://socratic.org/questions/in-1l-of-a-3m-solution-of-sodium-chloride-how-many-grams-of-sodium-chloride-are-	175.35 grams	start physical_unit 9 10 mass g qc_end physical_unit 7 7 1 2 volume qc_end physical_unit 9 10 5 6 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium chloride [IN] grams"}]	[{"type":"physical unit","value":"175.35 grams"}]	[{"type":"physical unit","value":"Volume [OF] sodium chloride solution [=] \\pu{1 L}"},{"type":"physical unit","value":"Molarity [OF] sodium chloride solution [=] \\pu{3 M}"}]	<h1 class="questionTitle" itemprop="name">In 1L of a 3M solution of sodium chloride, how many grams of sodium chloride are in the solution? </h1>	null	175.35 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#"3 M"#</mathjax> solution has <mathjax>#3#</mathjax> moles of solute per litre.</p> <p>The mass of one mole of <mathjax>#"NaCl"#</mathjax> equals the MW of <mathjax>#"NaCl"#</mathjax></p> <p><mathjax>#"MW" = 35.45 + 23 = "58.45 g/mol"#</mathjax></p> <p>The mass of <mathjax>#3#</mathjax> moles is</p> <p><mathjax>#"58.45 g/mol" xx "3 mol" = "175.35 g NaCl"#</mathjax></p> <p>or <mathjax>#"200 g"#</mathjax> rounded to one sigfig.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"175.35 g"#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#"3 M"#</mathjax> solution has <mathjax>#3#</mathjax> moles of solute per litre.</p> <p>The mass of one mole of <mathjax>#"NaCl"#</mathjax> equals the MW of <mathjax>#"NaCl"#</mathjax></p> <p><mathjax>#"MW" = 35.45 + 23 = "58.45 g/mol"#</mathjax></p> <p>The mass of <mathjax>#3#</mathjax> moles is</p> <p><mathjax>#"58.45 g/mol" xx "3 mol" = "175.35 g NaCl"#</mathjax></p> <p>or <mathjax>#"200 g"#</mathjax> rounded to one sigfig.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In 1L of a 3M solution of sodium chloride, how many grams of sodium chloride are in the solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="401836" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mm-4"><img alt="" class="" src="https://profilepictures.socratic.org/HvEacoQwTRuTItKdTnmp_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mm-4"> MM </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T05:18:24" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"175.35 g"#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#"3 M"#</mathjax> solution has <mathjax>#3#</mathjax> moles of solute per litre.</p> <p>The mass of one mole of <mathjax>#"NaCl"#</mathjax> equals the MW of <mathjax>#"NaCl"#</mathjax></p> <p><mathjax>#"MW" = 35.45 + 23 = "58.45 g/mol"#</mathjax></p> <p>The mass of <mathjax>#3#</mathjax> moles is</p> <p><mathjax>#"58.45 g/mol" xx "3 mol" = "175.35 g NaCl"#</mathjax></p> <p>or <mathjax>#"200 g"#</mathjax> rounded to one sigfig.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/401836" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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3,409	ab729ce4-6ddd-11ea-a0b0-ccda262736ce	https://socratic.org/questions/how-would-you-write-a-balanced-chemical-equation-for-ch4-reacting-with-oxygen-ga	CH4 + 2 O2 -> 2 H2O + CO2	start chemical_equation qc_end chemical_equation 9 9 qc_end substance 12 13 qc_end substance 16 16 qc_end substance 18 19 qc_end end	[{"type":"other","value":"Chemical Equation [OF] balanced chemical equation"}]	[{"type":"chemical equation","value":"CH4 + 2 O2 -> 2 H2O + CO2"}]	[{"type":"chemical equation","value":"CH4"},{"type":"substance name","value":"Oxygen gas"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Carbon dioxide"}]	<h1 class="questionTitle" itemprop="name">How would you write a balanced chemical equation for CH4 reacting with oxygen gas to produce water and carbon dioxide? </h1>	null	CH4 + 2 O2 -> 2 H2O + CO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations. </p> <p>If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction. </p> <ul> <li> <p>To the left of the arrow, we have our reactants.</p> </li> <li> <p>To the right of the arrow, we have our products.</p> </li> </ul> <p>The quantity of each individual element in the left must equal the quantity of each individual element in the right. </p> <p>So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction. </p> <p><mathjax>#CH_4#</mathjax> + <mathjax>#O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>Our reactants in this equation are <mathjax>#CH_4#</mathjax> and <mathjax>#O_2#</mathjax>. </p> <p>Our next step is to break these down into individual atoms. </p> <p>We have:</p> <ul> <li>1 C atom, 4 H atoms & 2 O atoms.</li> </ul> <p>If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense? </p> <p>Now we look to the other side of the equation. </p> <p>Here we see our products are <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>Again, we break these down into individual atoms again. </p> <p>We have:</p> <ul> <li>1 C atom, 2 H atom, 3 O atoms</li> </ul> <p>This isn't right? What's wrong? </p> <p>Yes, do you see it? We have more H atoms in the reactant side than the product side, and more O atoms in the product side than the reactant side. According to the Law of Conservation of Mass though, this isn't possible.</p> <p>So how do you suppose we fix this? </p> <p>We have to make the number of atoms on both sides equal, don't we? When we achieve this, we'll have a balanced equation.</p> <p>To change the number of atoms, we can place a number in front of it, known as the coefficient. This multiplies the number of every atom by whatever number you use as the coefficient. BEWARE however, that we can never change the subscript (the little number), because doing so changes the chemical.</p> <p>We have 1 C on both sides of the reaction - so this doesn't need to change. </p> <p>We have 4 H on the left, and 2 H on the right. To make them equal, we place a 2 in front of the <mathjax>#H_2O#</mathjax> like so; <mathjax>#2H_2O#</mathjax>. This gives us 4 H on both sides, but it also gives us another O, making the total 4 O on the right....but we still only have 2O on the left, don't we? </p> <p>Place a 2 in front of the <mathjax>#O_2#</mathjax> to make 4 O on the left. </p> <p>Now your reaction equation is balanced, and should look like this...</p> <p><mathjax>#CH_4#</mathjax> + <mathjax>#2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#2H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4#</mathjax> + <mathjax>#2#</mathjax> <mathjax>#O_2 ->#</mathjax> <mathjax>#2#</mathjax> <mathjax>#H_2O + CO_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you write a balanced chemical equation for CH4 reacting with oxygen gas to produce water and carbon dioxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="187693" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/adam-g-2"><img alt="" class="" src="https://lh6.googleusercontent.com/-11Xmkcbdbeo/AAAAAAAAAAI/AAAAAAAABGw/VTmkS1PoAmE/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/adam-g-2"> Adam G </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-13T01:35:34" itemprop="dateCreated"> Nov 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4#</mathjax> + <mathjax>#2#</mathjax> <mathjax>#O_2 ->#</mathjax> <mathjax>#2#</mathjax> <mathjax>#H_2O + CO_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187693" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="187733" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/priapusgluteus"><img alt="" class="" src="https://profilepictures.socratic.org/CakKegESyr9qNJH296gU_IMG_0831.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/priapusgluteus"> In Scientia Opportunitas </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-13T03:55:44" itemprop="dateCreated"> Nov 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4#</mathjax> + <mathjax>#2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#2H_2O#</mathjax></p> <p>This is the balanced reaction equation for the combustion of methane. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations. </p> <p>If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction. </p> <ul> <li> <p>To the left of the arrow, we have our reactants.</p> </li> <li> <p>To the right of the arrow, we have our products.</p> </li> </ul> <p>The quantity of each individual element in the left must equal the quantity of each individual element in the right. </p> <p>So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction. </p> <p><mathjax>#CH_4#</mathjax> + <mathjax>#O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>Our reactants in this equation are <mathjax>#CH_4#</mathjax> and <mathjax>#O_2#</mathjax>. </p> <p>Our next step is to break these down into individual atoms. </p> <p>We have:</p> <ul> <li>1 C atom, 4 H atoms & 2 O atoms.</li> </ul> <p>If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense? </p> <p>Now we look to the other side of the equation. </p> <p>Here we see our products are <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>Again, we break these down into individual atoms again. </p> <p>We have:</p> <ul> <li>1 C atom, 2 H atom, 3 O atoms</li> </ul> <p>This isn't right? What's wrong? </p> <p>Yes, do you see it? We have more H atoms in the reactant side than the product side, and more O atoms in the product side than the reactant side. According to the Law of Conservation of Mass though, this isn't possible.</p> <p>So how do you suppose we fix this? </p> <p>We have to make the number of atoms on both sides equal, don't we? When we achieve this, we'll have a balanced equation.</p> <p>To change the number of atoms, we can place a number in front of it, known as the coefficient. This multiplies the number of every atom by whatever number you use as the coefficient. BEWARE however, that we can never change the subscript (the little number), because doing so changes the chemical.</p> <p>We have 1 C on both sides of the reaction - so this doesn't need to change. </p> <p>We have 4 H on the left, and 2 H on the right. To make them equal, we place a 2 in front of the <mathjax>#H_2O#</mathjax> like so; <mathjax>#2H_2O#</mathjax>. This gives us 4 H on both sides, but it also gives us another O, making the total 4 O on the right....but we still only have 2O on the left, don't we? </p> <p>Place a 2 in front of the <mathjax>#O_2#</mathjax> to make 4 O on the left. </p> <p>Now your reaction equation is balanced, and should look like this...</p> <p><mathjax>#CH_4#</mathjax> + <mathjax>#2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#2H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187733" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 76830 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you write a balanced chemical equation for CH4 reacting with oxygen gas to produce water and carbon dioxide?	null
3,410	a8523a30-6ddd-11ea-b10e-ccda262736ce	https://socratic.org/questions/how-to-find-how-many-moles-are-in-an-ion	0.91 moles	start physical_unit 58 59 mole mol qc_end physical_unit 14 14 23 24 mass qc_end physical_unit 16 16 30 31 molar_mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Na+ ions [IN] moles"}]	[{"type":"physical unit","value":"0.91 moles"}]	[{"type":"physical unit","value":"Mass [OF] NaCl solution [=] \\pu{53.2 g}"},{"type":"physical unit","value":"Molar mass [OF] NaCl [=] \\pu{58.44 g/mol}"}]	<h1 class="questionTitle" itemprop="name">How to find how many moles are in an ion?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I am given the solution of NaCl and it has a mass of 53.2 g and a molar mass of 58.44 g. I already know to how to find the number of moles for the entire solution, but I also need to find the number of moles for Na + ions. How exactly to I go about doing that? Thanks in advance!</p></div> </h2> </div> </div>	0.91 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, so you know for a fact that it dissociates completely in aqueous solution to produce cations, which are positively charged ions, and anions, which are negatively charged ions. </p> <p>In this case, you know that <strong>one formula unit</strong> of <em>sodium chloride</em>, <mathjax>#"NaCl"#</mathjax>, contains <strong>one</strong> sodium cation, <mathjax>#"Na"^(+)#</mathjax>, and <strong>one</strong> chloride anion, <mathjax>#"Cl"^(-)#</mathjax>.</p> <p><img alt="http://socratic.org/questions/what-is-formula-unit" src="https://useruploads.socratic.org/TcC6zm1lTHK9DJCuIO78_IonicCompoundsNaCl_FU.png"/> </p> <p>This means that when you dissolve <strong>one mole</strong> of sodium chloride in water, you will get <strong>one mole</strong> of aqueous sodium cations and <strong>one mole</strong> of aqueous chloride anions.</p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>So, if <strong>every mole</strong> of sodium chloride produces <strong>One mole</strong> of sodium cations, it follows that the number of moles of sodium cation present in your solution will be equal to the number of moles of sodium chloride you dissolved to create this solution. </p> <p>More specifically, you know that you have </p> <blockquote> <p><mathjax>#53.2 color(red)(cancel(color(black)("g"))) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(purple)("molar mass of NaCl")) = "0.910 moles NaCl"#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.9103color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Na"^(+)/(1color(red)(cancel(color(black)("mole NaCl")))) = color(green)(\|bar(ul(color(white)(a/a)"0.910 moles Na"^(+)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of sodium chloride.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.910 moles Na"^(+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, so you know for a fact that it dissociates completely in aqueous solution to produce cations, which are positively charged ions, and anions, which are negatively charged ions. </p> <p>In this case, you know that <strong>one formula unit</strong> of <em>sodium chloride</em>, <mathjax>#"NaCl"#</mathjax>, contains <strong>one</strong> sodium cation, <mathjax>#"Na"^(+)#</mathjax>, and <strong>one</strong> chloride anion, <mathjax>#"Cl"^(-)#</mathjax>.</p> <p><img alt="http://socratic.org/questions/what-is-formula-unit" src="https://useruploads.socratic.org/TcC6zm1lTHK9DJCuIO78_IonicCompoundsNaCl_FU.png"/> </p> <p>This means that when you dissolve <strong>one mole</strong> of sodium chloride in water, you will get <strong>one mole</strong> of aqueous sodium cations and <strong>one mole</strong> of aqueous chloride anions.</p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>So, if <strong>every mole</strong> of sodium chloride produces <strong>One mole</strong> of sodium cations, it follows that the number of moles of sodium cation present in your solution will be equal to the number of moles of sodium chloride you dissolved to create this solution. </p> <p>More specifically, you know that you have </p> <blockquote> <p><mathjax>#53.2 color(red)(cancel(color(black)("g"))) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(purple)("molar mass of NaCl")) = "0.910 moles NaCl"#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.9103color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Na"^(+)/(1color(red)(cancel(color(black)("mole NaCl")))) = color(green)(\|bar(ul(color(white)(a/a)"0.910 moles Na"^(+)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of sodium chloride.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How to find how many moles are in an ion?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I am given the solution of NaCl and it has a mass of 53.2 g and a molar mass of 58.44 g. I already know to how to find the number of moles for the entire solution, but I also need to find the number of moles for Na + ions. How exactly to I go about doing that? Thanks in advance!</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="246924" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-29T19:48:18" itemprop="dateCreated"> Mar 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.910 moles Na"^(+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, so you know for a fact that it dissociates completely in aqueous solution to produce cations, which are positively charged ions, and anions, which are negatively charged ions. </p> <p>In this case, you know that <strong>one formula unit</strong> of <em>sodium chloride</em>, <mathjax>#"NaCl"#</mathjax>, contains <strong>one</strong> sodium cation, <mathjax>#"Na"^(+)#</mathjax>, and <strong>one</strong> chloride anion, <mathjax>#"Cl"^(-)#</mathjax>.</p> <p><img alt="http://socratic.org/questions/what-is-formula-unit" src="https://useruploads.socratic.org/TcC6zm1lTHK9DJCuIO78_IonicCompoundsNaCl_FU.png"/> </p> <p>This means that when you dissolve <strong>one mole</strong> of sodium chloride in water, you will get <strong>one mole</strong> of aqueous sodium cations and <strong>one mole</strong> of aqueous chloride anions.</p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>So, if <strong>every mole</strong> of sodium chloride produces <strong>One mole</strong> of sodium cations, it follows that the number of moles of sodium cation present in your solution will be equal to the number of moles of sodium chloride you dissolved to create this solution. </p> <p>More specifically, you know that you have </p> <blockquote> <p><mathjax>#53.2 color(red)(cancel(color(black)("g"))) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(purple)("molar mass of NaCl")) = "0.910 moles NaCl"#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.9103color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Na"^(+)/(1color(red)(cancel(color(black)("mole NaCl")))) = color(green)(\|bar(ul(color(white)(a/a)"0.910 moles Na"^(+)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of sodium chloride.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/246924" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 74027 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How to find how many moles are in an ion?	I am given the solution of NaCl and it has a mass of 53.2 g and a molar mass of 58.44 g. I already know to how to find the number of moles for the entire solution, but I also need to find the number of moles for Na + ions. How exactly to I go about doing that? Thanks in advance!
3,411	abf55d3a-6ddd-11ea-8c79-ccda262736ce	https://socratic.org/questions/if-a-gas-sample-in-a-balloon-had-a-volume-of-100-and-a-pressure-of-3-atm-it-ml-w	30.00 mL	start physical_unit 2 3 volume ml qc_end physical_unit 2 3 11 12 volume qc_end physical_unit 2 3 17 18 pressure qc_end physical_unit 2 3 28 29 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas sample [IN] mL"}]	[{"type":"physical unit","value":"30.00 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{100 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{3 atm}"},{"type":"physical unit","value":"Pressure2 [OF] the gas sample [=] \\pu{10 atm}"}]	<h1 class="questionTitle" itemprop="name">If a gas sample in a balloon had a volume of 100 and a pressure of 3 atm. It mL was then compressed to a pressure of 10 atm, what would be its volume?</h1>	null	30.00 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's gas law will allow us to find the answer. <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that the volume of a given amount of gas varies inversely with the applied pressure, as long as temperature and mass are held constant. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Given</strong><br/> <mathjax>#P_1="3 atm"#</mathjax><br/> <mathjax>#V_1="100 mL"#</mathjax><br/> <mathjax>#P_2="10 atm"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Insert the given data and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(3color(red)cancel(color(black)("atm"))xx100"mL")/(10color(red)cancel(color(black)("atm")))="30 mL"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume of the gas will be <mathjax>#"30 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's gas law will allow us to find the answer. <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that the volume of a given amount of gas varies inversely with the applied pressure, as long as temperature and mass are held constant. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Given</strong><br/> <mathjax>#P_1="3 atm"#</mathjax><br/> <mathjax>#V_1="100 mL"#</mathjax><br/> <mathjax>#P_2="10 atm"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Insert the given data and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(3color(red)cancel(color(black)("atm"))xx100"mL")/(10color(red)cancel(color(black)("atm")))="30 mL"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a gas sample in a balloon had a volume of 100 and a pressure of 3 atm. It mL was then compressed to a pressure of 10 atm, what would be its volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421882" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-12T02:32:33" itemprop="dateCreated"> May 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume of the gas will be <mathjax>#"30 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's gas law will allow us to find the answer. <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that the volume of a given amount of gas varies inversely with the applied pressure, as long as temperature and mass are held constant. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Given</strong><br/> <mathjax>#P_1="3 atm"#</mathjax><br/> <mathjax>#V_1="100 mL"#</mathjax><br/> <mathjax>#P_2="10 atm"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Insert the given data and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(3color(red)cancel(color(black)("atm"))xx100"mL")/(10color(red)cancel(color(black)("atm")))="30 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421882" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3842 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If a gas sample in a balloon had a volume of 100 and a pressure of 3 atm. It mL was then compressed to a pressure of 10 atm, what would be its volume?	null
3,412	a8ce5ad0-6ddd-11ea-aa95-ccda262736ce	https://socratic.org/questions/20-cubic-meters-of-hydrogen-gas-at-100-k-is-heated-under-constant-pressure-to-20	40 cubic meters	start physical_unit 24 26 volume m^3 qc_end physical_unit 5 6 1 3 volume qc_end physical_unit 5 6 8 9 temperature qc_end c_other OTHER qc_end physical_unit 5 6 16 17 temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the hydrogen gas [IN] cubic meters"}]	[{"type":"physical unit","value":"40 cubic meters"}]	[{"type":"physical unit","value":"Volume1 [OF] hydrogen gas [=] \\pu{20 cubic meters}"},{"type":"physical unit","value":"Temperature1 [OF] hydrogen gas [=] \\pu{100 K}"},{"type":"other","value":"Constant pressure"},{"type":"physical unit","value":"Temperature2 [OF] hydrogen gas [=] \\pu{200 K}"}]	<h1 class="questionTitle" itemprop="name">20 cubic meters of hydrogen gas at 100 K is heated under constant pressure to 200 K. What is the new volume of the hydrogen gas? </h1>	null	40 cubic meters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I tried using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> collecting <mathjax>#nR#</mathjax> between the initial and final state:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/duU5N6HT2qvRJo3vEP7Q_idealgas.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#40m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I tried using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> collecting <mathjax>#nR#</mathjax> between the initial and final state:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/duU5N6HT2qvRJo3vEP7Q_idealgas.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">20 cubic meters of hydrogen gas at 100 K is heated under constant pressure to 200 K. What is the new volume of the hydrogen gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="215100" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T15:26:32" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#40m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I tried using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> collecting <mathjax>#nR#</mathjax> between the initial and final state:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/duU5N6HT2qvRJo3vEP7Q_idealgas.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/215100" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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What is the new volume of the hydrogen gas?	null
3,413	aa108230-6ddd-11ea-9890-ccda262736ce	https://socratic.org/questions/the-molar-heat-of-fusion-for-water-is-6-01-kj-mol-how-much-energy-is-released-wh	12.28 kJ	start physical_unit 6 6 heat_energy kj qc_end physical_unit 6 6 8 9 molar_heat qc_end physical_unit 6 6 16 17 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Released energy [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"12.28 kJ"}]	[{"type":"physical unit","value":"Molar heat of fusion [OF] water [=] \\pu{6.01 kJ/mol}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{36.8 g}"},{"type":"other","value":"Water freezes at its freezing point."}]	<h1 class="questionTitle" itemprop="name">The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point?</h1>	null	12.28 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar heat of fusion</strong> basically tells you one thing from <em>two perspectives</em></p> <ul> <li><em>how much heat is <strong>needed</strong> in order to melt <strong>one mole</strong> of that substance at its melting point</em></li> <li><em>how much heat must be <strong>removed</strong> in order to freeze <strong>one mole</strong> of that substance at its freezing point</em></li> </ul> <p>It is <strong>very important</strong> to realize that the molar <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion will carry a <strong>positive sign</strong> when you're dealing with <em>melting</em> and a <strong>negative sign</strong> when you're dealing with <em>freezing</em>. </p> <p>That is the case because <strong>heat released</strong> carries a negative sign, while <strong>heat absorbed</strong> carries a positive sign. So, for water, you can say that</p> <blockquote> <p><mathjax>#DeltaH_"fus" = +"6.01 kJ/mol" ->#</mathjax> <em>heat needed for melting</em></p> <p><mathjax>#DeltaH_"fus" = -"6.01 kJ/mol" ->#</mathjax> <em>heat released when freezing</em></p> </blockquote> <p>You're interested in finding out how much heat is <strong>released</strong> when <mathjax>#"36.8 g"#</mathjax> of water freeze at water's freezing point. The first thing to do here is use water's <strong>molar mass</strong> to calculate how many moles you have in that sample</p> <blockquote> <p><mathjax>#36.8 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.043 moles H"_2"O"#</mathjax></p> </blockquote> <p>The heat released can be calculated using the equation</p> <blockquote> <p><mathjax>#color(blue)(q = n * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat released<br/> <mathjax>#n#</mathjax> - the number of moles of the substance<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the molar enthalpy of fusion for that substance</p> <p>Since you're dealing with <strong>freezing</strong>, you will have </p> <blockquote> <p><mathjax>#q = 2.043 color(red)(cancel(color(black)("moles"))) * (-6.01"kJ"/color(red)(cancel(color(black)("mol")))) = -"12.3 kJ"#</mathjax></p> </blockquote> <p>What this means is that when <mathjax>#"36.8 g"#</mathjax> of water <strong>freeze</strong> at water's freezing point, <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong> to the surroundings. </p> <p>Remember, the <em>negative sign</em> symbolizes heat <strong>released</strong>. </p> <p>Having</p> <blockquote> <p><mathjax>#q = -"12.3 kJ"#</mathjax> </p> </blockquote> <p>is equivalent to saying that <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"12.3 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar heat of fusion</strong> basically tells you one thing from <em>two perspectives</em></p> <ul> <li><em>how much heat is <strong>needed</strong> in order to melt <strong>one mole</strong> of that substance at its melting point</em></li> <li><em>how much heat must be <strong>removed</strong> in order to freeze <strong>one mole</strong> of that substance at its freezing point</em></li> </ul> <p>It is <strong>very important</strong> to realize that the molar <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion will carry a <strong>positive sign</strong> when you're dealing with <em>melting</em> and a <strong>negative sign</strong> when you're dealing with <em>freezing</em>. </p> <p>That is the case because <strong>heat released</strong> carries a negative sign, while <strong>heat absorbed</strong> carries a positive sign. So, for water, you can say that</p> <blockquote> <p><mathjax>#DeltaH_"fus" = +"6.01 kJ/mol" ->#</mathjax> <em>heat needed for melting</em></p> <p><mathjax>#DeltaH_"fus" = -"6.01 kJ/mol" ->#</mathjax> <em>heat released when freezing</em></p> </blockquote> <p>You're interested in finding out how much heat is <strong>released</strong> when <mathjax>#"36.8 g"#</mathjax> of water freeze at water's freezing point. The first thing to do here is use water's <strong>molar mass</strong> to calculate how many moles you have in that sample</p> <blockquote> <p><mathjax>#36.8 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.043 moles H"_2"O"#</mathjax></p> </blockquote> <p>The heat released can be calculated using the equation</p> <blockquote> <p><mathjax>#color(blue)(q = n * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat released<br/> <mathjax>#n#</mathjax> - the number of moles of the substance<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the molar enthalpy of fusion for that substance</p> <p>Since you're dealing with <strong>freezing</strong>, you will have </p> <blockquote> <p><mathjax>#q = 2.043 color(red)(cancel(color(black)("moles"))) * (-6.01"kJ"/color(red)(cancel(color(black)("mol")))) = -"12.3 kJ"#</mathjax></p> </blockquote> <p>What this means is that when <mathjax>#"36.8 g"#</mathjax> of water <strong>freeze</strong> at water's freezing point, <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong> to the surroundings. </p> <p>Remember, the <em>negative sign</em> symbolizes heat <strong>released</strong>. </p> <p>Having</p> <blockquote> <p><mathjax>#q = -"12.3 kJ"#</mathjax> </p> </blockquote> <p>is equivalent to saying that <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216951" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T19:08:23" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"12.3 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar heat of fusion</strong> basically tells you one thing from <em>two perspectives</em></p> <ul> <li><em>how much heat is <strong>needed</strong> in order to melt <strong>one mole</strong> of that substance at its melting point</em></li> <li><em>how much heat must be <strong>removed</strong> in order to freeze <strong>one mole</strong> of that substance at its freezing point</em></li> </ul> <p>It is <strong>very important</strong> to realize that the molar <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion will carry a <strong>positive sign</strong> when you're dealing with <em>melting</em> and a <strong>negative sign</strong> when you're dealing with <em>freezing</em>. </p> <p>That is the case because <strong>heat released</strong> carries a negative sign, while <strong>heat absorbed</strong> carries a positive sign. So, for water, you can say that</p> <blockquote> <p><mathjax>#DeltaH_"fus" = +"6.01 kJ/mol" ->#</mathjax> <em>heat needed for melting</em></p> <p><mathjax>#DeltaH_"fus" = -"6.01 kJ/mol" ->#</mathjax> <em>heat released when freezing</em></p> </blockquote> <p>You're interested in finding out how much heat is <strong>released</strong> when <mathjax>#"36.8 g"#</mathjax> of water freeze at water's freezing point. The first thing to do here is use water's <strong>molar mass</strong> to calculate how many moles you have in that sample</p> <blockquote> <p><mathjax>#36.8 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.043 moles H"_2"O"#</mathjax></p> </blockquote> <p>The heat released can be calculated using the equation</p> <blockquote> <p><mathjax>#color(blue)(q = n * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat released<br/> <mathjax>#n#</mathjax> - the number of moles of the substance<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the molar enthalpy of fusion for that substance</p> <p>Since you're dealing with <strong>freezing</strong>, you will have </p> <blockquote> <p><mathjax>#q = 2.043 color(red)(cancel(color(black)("moles"))) * (-6.01"kJ"/color(red)(cancel(color(black)("mol")))) = -"12.3 kJ"#</mathjax></p> </blockquote> <p>What this means is that when <mathjax>#"36.8 g"#</mathjax> of water <strong>freeze</strong> at water's freezing point, <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong> to the surroundings. </p> <p>Remember, the <em>negative sign</em> symbolizes heat <strong>released</strong>. </p> <p>Having</p> <blockquote> <p><mathjax>#q = -"12.3 kJ"#</mathjax> </p> </blockquote> <p>is equivalent to saying that <mathjax>#"12.3 kJ"#</mathjax> of heat are being <strong>released</strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216951" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 66943 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point?	null
3,414	a9a5b438-6ddd-11ea-8669-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-0-175-moles-of-phosphorus	5.43 grams	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] phosphorus [IN] grams"}]	[{"type":"physical unit","value":"5.43 grams"}]	[{"type":"physical unit","value":"Mole [OF] phosphorus [=] \\pu{0.175 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 0.175 moles of phosphorus?</h1>	null	5.43 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The average mass of one mole of Phosphorus <mathjax>#(P)#</mathjax> <mathjax>#=31grams.#</mathjax> </p> <p><mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=#</mathjax>(Molar mass)<mathjax>#xx#</mathjax>(No. of moles).<br/> <mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=(31g) xx (0.175)=5.425grams.#</mathjax> (answer)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> is <mathjax>#5.425grams.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The average mass of one mole of Phosphorus <mathjax>#(P)#</mathjax> <mathjax>#=31grams.#</mathjax> </p> <p><mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=#</mathjax>(Molar mass)<mathjax>#xx#</mathjax>(No. of moles).<br/> <mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=(31g) xx (0.175)=5.425grams.#</mathjax> (answer)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 0.175 moles of phosphorus?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="331841" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/aditya-9"><img alt="" class="" src="https://profilepictures.socratic.org/JI8xltWvSDeHqZTzxqDb_25.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/aditya-9"> Aditya Banerjee. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-05T15:23:50" itemprop="dateCreated"> Nov 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> is <mathjax>#5.425grams.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The average mass of one mole of Phosphorus <mathjax>#(P)#</mathjax> <mathjax>#=31grams.#</mathjax> </p> <p><mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=#</mathjax>(Molar mass)<mathjax>#xx#</mathjax>(No. of moles).<br/> <mathjax>#:.#</mathjax> Mass of <mathjax>#0.175#</mathjax> moles of <mathjax>#P#</mathjax> <mathjax>#=(31g) xx (0.175)=5.425grams.#</mathjax> (answer)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/331841" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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3,415	ac9ca6cd-6ddd-11ea-95fb-ccda262736ce	https://socratic.org/questions/a-sample-that-contains-3-66-mol-of-a-gas-at-265-k-has-a-pressure-of-1-09-atm-wha	73.1 L	start physical_unit 8 8 volume l qc_end physical_unit 8 8 4 5 mole qc_end physical_unit 8 8 10 11 temperature qc_end physical_unit 8 8 16 17 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] the gas sample [IN] L"}]	[{"type":"physical unit","value":"73.1 L"}]	[{"type":"physical unit","value":"Mole [OF] the gas sample [=] \\pu{3.66 mol}"},{"type":"physical unit","value":"Temperature [OF] the gas sample [=] \\pu{265 K}"},{"type":"physical unit","value":"Pressure [OF] the gas sample [=] \\pu{1.09 atm}"}]	<h1 class="questionTitle" itemprop="name">A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume? </h1>	null	73.1 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. The equation for the ideal gas law is <mathjax>#PV=nRT#</mathjax>, where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="1.09 atm"#</mathjax><br/> <mathjax>#n="3.66 moles gas"#</mathjax><br/> <mathjax>#R=0.082057338("L·atm")/("K·mol")#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="265 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the gas is 73.1 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. The equation for the ideal gas law is <mathjax>#PV=nRT#</mathjax>, where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="1.09 atm"#</mathjax><br/> <mathjax>#n="3.66 moles gas"#</mathjax><br/> <mathjax>#R=0.082057338("L·atm")/("K·mol")#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="265 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238063" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T05:24:33" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the gas is 73.1 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. The equation for the ideal gas law is <mathjax>#PV=nRT#</mathjax>, where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="1.09 atm"#</mathjax><br/> <mathjax>#n="3.66 moles gas"#</mathjax><br/> <mathjax>#R=0.082057338("L·atm")/("K·mol")#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="265 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238063" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3576 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?	null
3,416	a93b0910-6ddd-11ea-8cc9-ccda262736ce	https://socratic.org/questions/you-heat-0-158g-of-a-white-solid-carbonate-of-a-group-2-metal-and-find-that-the-	87.71 g/mol	start physical_unit 40 42 molar_mass g/mol qc_end physical_unit 5 8 2 3 mass qc_end physical_unit 19 19 24 25 pressure qc_end physical_unit 30 30 28 29 volume qc_end physical_unit 19 19 32 33 temperature qc_end end	[{"type":"physical unit","value":"Molar mass [OF] the metal carbonate [IN] g/mol"}]	[{"type":"physical unit","value":"87.71 g/mol"}]	[{"type":"physical unit","value":"Mass [OF] a white, solid carbonate [=] \\pu{0.158 g}"},{"type":"physical unit","value":"Pressure [OF] CO2 [=] \\pu{69.8 mmHg}"},{"type":"physical unit","value":"Volume [OF] flask [=] \\pu{285 ml}"},{"type":"physical unit","value":"Temperature [OF] CO2 [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8 mmHg In a 285ml flask at 25°C .What is the molar mass of the metal carbonate?</h1>	null	87.71 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many moles of carbon dioxide were produced by this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where </p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas <br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas <br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821 ("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas</p> <p>Now, it is of the utmost importance to make sure that you convert all the units given to you to those used by the universal gas constant! </p> <p>In this case, you need to convert the pressure from <em>mmHg</em> to <em>atm</em>, the volume from <em>milliliters</em> to <em>liters</em>, and the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>. </p> <p>This will get you </p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3) color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25)color(red)(cancel(color(black)("K")))) = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>Next, you need to write a <strong>general form</strong> balanced chemical equation for the decomposition of this carbonate. Group 2 metal cations have a <mathjax>#2+#</mathjax> charge, which means that you can represent the carbonate as <mathjax>#"MCO"_3#</mathjax>. </p> <p>Now, group 2 carbonates will undergo decomposition to form the metal oxide and carbon dioxide. This means that you can write </p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) -> "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between all the chemical species that take part in the reaction. This means that if the reaction <strong>produced</strong> <mathjax>#0.001069#</mathjax> moles of <mathjax>#"CO"_2#</mathjax>, then it must have also <strong>consumed</strong> <mathjax>#0.001069#</mathjax> moles of metal carbonate. </p> <p>Since you know the <strong>mass</strong> of the metal carbonate sample, you can find its <em>molar mass</em> by dividing this value by the number of moles that it contained. Simply put, <strong>one mole</strong> of metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("moles MCO"_3))) * "0.158 g"/(0.001069 color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Finally, use the molar mass of the <em>carbonate anion</em>, <mathjax>#"CO"_3^(2-)#</mathjax>, to find the molar mass of the metal, <mathjax>#"M"#</mathjax>. </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.0107 g/mol")^(color(blue)("one atom of carbon")) + overbrace(3 xx "15.9994 g/mol")^(color(red)("three atoms of oxygen")) = "60.09 g/mol"#</mathjax></p> </blockquote> <p>Therefore, the molar mass of the metal is </p> <blockquote> <p><mathjax>#"147.8 g/mol" - "60.09 g/mol" = color(green)("87.71 g/mol")#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to four <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>. </p> <p>The closest match to this value is <em>strontium</em>, <mathjax>#"Sr"#</mathjax>, which has a molar mass of <mathjax>#"87.62 g/mol"#</mathjax>. </p> <p>Therefore, your metal carbonate was <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"87.71 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many moles of carbon dioxide were produced by this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where </p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas <br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas <br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821 ("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas</p> <p>Now, it is of the utmost importance to make sure that you convert all the units given to you to those used by the universal gas constant! </p> <p>In this case, you need to convert the pressure from <em>mmHg</em> to <em>atm</em>, the volume from <em>milliliters</em> to <em>liters</em>, and the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>. </p> <p>This will get you </p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3) color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25)color(red)(cancel(color(black)("K")))) = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>Next, you need to write a <strong>general form</strong> balanced chemical equation for the decomposition of this carbonate. Group 2 metal cations have a <mathjax>#2+#</mathjax> charge, which means that you can represent the carbonate as <mathjax>#"MCO"_3#</mathjax>. </p> <p>Now, group 2 carbonates will undergo decomposition to form the metal oxide and carbon dioxide. This means that you can write </p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) -> "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between all the chemical species that take part in the reaction. This means that if the reaction <strong>produced</strong> <mathjax>#0.001069#</mathjax> moles of <mathjax>#"CO"_2#</mathjax>, then it must have also <strong>consumed</strong> <mathjax>#0.001069#</mathjax> moles of metal carbonate. </p> <p>Since you know the <strong>mass</strong> of the metal carbonate sample, you can find its <em>molar mass</em> by dividing this value by the number of moles that it contained. Simply put, <strong>one mole</strong> of metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("moles MCO"_3))) * "0.158 g"/(0.001069 color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Finally, use the molar mass of the <em>carbonate anion</em>, <mathjax>#"CO"_3^(2-)#</mathjax>, to find the molar mass of the metal, <mathjax>#"M"#</mathjax>. </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.0107 g/mol")^(color(blue)("one atom of carbon")) + overbrace(3 xx "15.9994 g/mol")^(color(red)("three atoms of oxygen")) = "60.09 g/mol"#</mathjax></p> </blockquote> <p>Therefore, the molar mass of the metal is </p> <blockquote> <p><mathjax>#"147.8 g/mol" - "60.09 g/mol" = color(green)("87.71 g/mol")#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to four <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>. </p> <p>The closest match to this value is <em>strontium</em>, <mathjax>#"Sr"#</mathjax>, which has a molar mass of <mathjax>#"87.62 g/mol"#</mathjax>. </p> <p>Therefore, your metal carbonate was <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8 mmHg In a 285ml flask at 25°C .What is the molar mass of the metal carbonate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="195653" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-03T02:56:12" itemprop="dateCreated"> Dec 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"87.71 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many moles of carbon dioxide were produced by this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where </p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas <br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas <br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821 ("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas</p> <p>Now, it is of the utmost importance to make sure that you convert all the units given to you to those used by the universal gas constant! </p> <p>In this case, you need to convert the pressure from <em>mmHg</em> to <em>atm</em>, the volume from <em>milliliters</em> to <em>liters</em>, and the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>. </p> <p>This will get you </p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3) color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25)color(red)(cancel(color(black)("K")))) = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>Next, you need to write a <strong>general form</strong> balanced chemical equation for the decomposition of this carbonate. Group 2 metal cations have a <mathjax>#2+#</mathjax> charge, which means that you can represent the carbonate as <mathjax>#"MCO"_3#</mathjax>. </p> <p>Now, group 2 carbonates will undergo decomposition to form the metal oxide and carbon dioxide. This means that you can write </p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) -> "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between all the chemical species that take part in the reaction. This means that if the reaction <strong>produced</strong> <mathjax>#0.001069#</mathjax> moles of <mathjax>#"CO"_2#</mathjax>, then it must have also <strong>consumed</strong> <mathjax>#0.001069#</mathjax> moles of metal carbonate. </p> <p>Since you know the <strong>mass</strong> of the metal carbonate sample, you can find its <em>molar mass</em> by dividing this value by the number of moles that it contained. Simply put, <strong>one mole</strong> of metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("moles MCO"_3))) * "0.158 g"/(0.001069 color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Finally, use the molar mass of the <em>carbonate anion</em>, <mathjax>#"CO"_3^(2-)#</mathjax>, to find the molar mass of the metal, <mathjax>#"M"#</mathjax>. </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.0107 g/mol")^(color(blue)("one atom of carbon")) + overbrace(3 xx "15.9994 g/mol")^(color(red)("three atoms of oxygen")) = "60.09 g/mol"#</mathjax></p> </blockquote> <p>Therefore, the molar mass of the metal is </p> <blockquote> <p><mathjax>#"147.8 g/mol" - "60.09 g/mol" = color(green)("87.71 g/mol")#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to four <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>. </p> <p>The closest match to this value is <em>strontium</em>, <mathjax>#"Sr"#</mathjax>, which has a molar mass of <mathjax>#"87.62 g/mol"#</mathjax>. </p> <p>Therefore, your metal carbonate was <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195653" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2089 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8 mmHg In a 285ml flask at 25°C .What is the molar mass of the metal carbonate?	null
3,417	a84a9a71-6ddd-11ea-bfb2-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-0-5-mole-of-co2	22 grams	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]	[{"type":"physical unit","value":"22 grams"}]	[{"type":"physical unit","value":"Mole [OF] CO2 [=] \\pu{0.5 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 0.5 moles of #"CO"_2# ?</h1>	null	22 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 0.5 moles of #"CO"_2# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="635755" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/joshua-b-3"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/joshua-b-3"> Joshua B. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-26T11:52:50" itemprop="dateCreated"> Jun 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/635755" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="636253" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-27T10:26:02" itemprop="dateCreated"> Jun 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the mass of a certain number of moles of a substance, we multiply the number of moles of the substance by its molar mass.</p> <p>Carbon dioxide <mathjax>#(CO_2)#</mathjax> has a molar mass of <mathjax>#44.01 \ "g/mol"#</mathjax>. Here, there are <mathjax>#0.5 \ "mol"#</mathjax> of the molecule. So, the mass of this sample is:</p> <p><mathjax>#m=(44.01 \ "g")/(color(red)cancelcolor(black)"mol")*0.5color(red)cancelcolor(black)"mol"#</mathjax></p> <p><mathjax>#~~22 \ "g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/636253" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26859 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of 0.5 moles of #"CO"_2# ?	null
3,418	aad1b82d-6ddd-11ea-a6fe-ccda262736ce	https://socratic.org/questions/what-volume-of-0-25-m-hcl-solution-must-be-diluted-to-prepare-1-00-l-of-0-040-m-	160 mL	start physical_unit 5 6 volume ml qc_end physical_unit 5 6 15 16 molarity qc_end physical_unit 5 6 3 4 molarity qc_end physical_unit 5 6 12 13 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] HCl solution [IN] mL"}]	[{"type":"physical unit","value":"160 mL"}]	[{"type":"physical unit","value":"Molarity1 [OF] HCl solution [=] \\pu{0.040 M}"},{"type":"physical unit","value":"Molarity2 [OF] HCl solution [=] \\pu{0.25 M}"},{"type":"physical unit","value":"Volume1 [OF] HCl solution [=] \\pu{1.00 L}"}]	<h1 class="questionTitle" itemprop="name">What volume of 0.25 M #HCl# solution must be diluted to prepare 1.00 L of 0.040 M #HCl#?</h1>	null	160 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to keep in mind when it comes to <em>diluting <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a></em> is that the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> at all times. </p> <p>Simply put, the number of moles of solute present in the <em>dilute solution</em> must be <strong>equal to</strong> the number of moles of solute present in the <em>concentrated sample</em>. </p> <p>This is the key to any <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculation</a></strong>. As you know, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>In essence, when you <em>dilute</em> a solution, you <strong>decrease</strong> its concentration by <strong>increasing</strong> its volume, which in turn is done by adding more <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong> to the solution.</p> <p><mathjax>#color(white)(a)#</mathjax></p> <p><img alt="http://www.alloprof.qc.ca/BV/pages/s1054.aspx" src="https://useruploads.socratic.org/YJ7Eb2bSSqRd3WNFagQi_s1054i1.jpg"/> </p> <p><mathjax>#color(white)(a)#</mathjax></p> <p>So, you know the molarity and volume of the target solution, which means that you can determine how many moles of hydrochloric acid it must contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.040 mol" color(red)(cancel(color(black)("L"^(-1)))) * 1.00color(red)(cancel(color(black)("L"))) = "0.040 moles HCl"#</mathjax></p> </blockquote> <p>Now your task is to determine what <strong>volume</strong> of the concentrated solution would contain this many moles of hydrochloric acid.</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (0.040color(red)(cancel(color(black)("moles"))))/(0.25color(red)(cancel(color(black)("mol")))"L"^(-1)) = "0.16 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em> and rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("160 mL")#</mathjax></p> </blockquote> <p>This is exactly what the formula for <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></em> allows you to do</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(black)("moles of solute in concentrated solution")) = overbrace(c_2 xx V_2)^(color(black)("moles of solute in diluted solution"))#</mathjax></p> </blockquote> <p>Here you have</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the molarity and volume of the concentrated solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the molarity and volume of the diluted solution</p> <p>Once again you will have</p> <blockquote> <p><mathjax>#V_1 = c_2/c_1 * V_2#</mathjax></p> <p><mathjax>#V_1 = (0.040color(red)(cancel(color(black)("M"))))/(0.025color(red)(cancel(color(black)("M")))) * "1.00 L" = color(green)("160 mL")#</mathjax></p> </blockquote> <p>So, you would prepare this solution by adding enough water to your <mathjax>#"160-mL"#</mathjax> sample of <mathjax>#"0.25-M"#</mathjax> hydrochloric acid solution to make the total volume of the resulting solution equal to <mathjax>#"1.00 L"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"160 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to keep in mind when it comes to <em>diluting <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a></em> is that the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> at all times. </p> <p>Simply put, the number of moles of solute present in the <em>dilute solution</em> must be <strong>equal to</strong> the number of moles of solute present in the <em>concentrated sample</em>. </p> <p>This is the key to any <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculation</a></strong>. As you know, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>In essence, when you <em>dilute</em> a solution, you <strong>decrease</strong> its concentration by <strong>increasing</strong> its volume, which in turn is done by adding more <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong> to the solution.</p> <p><mathjax>#color(white)(a)#</mathjax></p> <p><img alt="http://www.alloprof.qc.ca/BV/pages/s1054.aspx" src="https://useruploads.socratic.org/YJ7Eb2bSSqRd3WNFagQi_s1054i1.jpg"/> </p> <p><mathjax>#color(white)(a)#</mathjax></p> <p>So, you know the molarity and volume of the target solution, which means that you can determine how many moles of hydrochloric acid it must contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.040 mol" color(red)(cancel(color(black)("L"^(-1)))) * 1.00color(red)(cancel(color(black)("L"))) = "0.040 moles HCl"#</mathjax></p> </blockquote> <p>Now your task is to determine what <strong>volume</strong> of the concentrated solution would contain this many moles of hydrochloric acid.</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (0.040color(red)(cancel(color(black)("moles"))))/(0.25color(red)(cancel(color(black)("mol")))"L"^(-1)) = "0.16 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em> and rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("160 mL")#</mathjax></p> </blockquote> <p>This is exactly what the formula for <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></em> allows you to do</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(black)("moles of solute in concentrated solution")) = overbrace(c_2 xx V_2)^(color(black)("moles of solute in diluted solution"))#</mathjax></p> </blockquote> <p>Here you have</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the molarity and volume of the concentrated solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the molarity and volume of the diluted solution</p> <p>Once again you will have</p> <blockquote> <p><mathjax>#V_1 = c_2/c_1 * V_2#</mathjax></p> <p><mathjax>#V_1 = (0.040color(red)(cancel(color(black)("M"))))/(0.025color(red)(cancel(color(black)("M")))) * "1.00 L" = color(green)("160 mL")#</mathjax></p> </blockquote> <p>So, you would prepare this solution by adding enough water to your <mathjax>#"160-mL"#</mathjax> sample of <mathjax>#"0.25-M"#</mathjax> hydrochloric acid solution to make the total volume of the resulting solution equal to <mathjax>#"1.00 L"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of 0.25 M #HCl# solution must be diluted to prepare 1.00 L of 0.040 M #HCl#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="231174" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-26T02:11:00" itemprop="dateCreated"> Feb 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"160 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to keep in mind when it comes to <em>diluting <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a></em> is that the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> at all times. </p> <p>Simply put, the number of moles of solute present in the <em>dilute solution</em> must be <strong>equal to</strong> the number of moles of solute present in the <em>concentrated sample</em>. </p> <p>This is the key to any <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculation</a></strong>. As you know, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>In essence, when you <em>dilute</em> a solution, you <strong>decrease</strong> its concentration by <strong>increasing</strong> its volume, which in turn is done by adding more <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong> to the solution.</p> <p><mathjax>#color(white)(a)#</mathjax></p> <p><img alt="http://www.alloprof.qc.ca/BV/pages/s1054.aspx" src="https://useruploads.socratic.org/YJ7Eb2bSSqRd3WNFagQi_s1054i1.jpg"/> </p> <p><mathjax>#color(white)(a)#</mathjax></p> <p>So, you know the molarity and volume of the target solution, which means that you can determine how many moles of hydrochloric acid it must contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.040 mol" color(red)(cancel(color(black)("L"^(-1)))) * 1.00color(red)(cancel(color(black)("L"))) = "0.040 moles HCl"#</mathjax></p> </blockquote> <p>Now your task is to determine what <strong>volume</strong> of the concentrated solution would contain this many moles of hydrochloric acid.</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (0.040color(red)(cancel(color(black)("moles"))))/(0.25color(red)(cancel(color(black)("mol")))"L"^(-1)) = "0.16 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em> and rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("160 mL")#</mathjax></p> </blockquote> <p>This is exactly what the formula for <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></em> allows you to do</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(black)("moles of solute in concentrated solution")) = overbrace(c_2 xx V_2)^(color(black)("moles of solute in diluted solution"))#</mathjax></p> </blockquote> <p>Here you have</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the molarity and volume of the concentrated solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the molarity and volume of the diluted solution</p> <p>Once again you will have</p> <blockquote> <p><mathjax>#V_1 = c_2/c_1 * V_2#</mathjax></p> <p><mathjax>#V_1 = (0.040color(red)(cancel(color(black)("M"))))/(0.025color(red)(cancel(color(black)("M")))) * "1.00 L" = color(green)("160 mL")#</mathjax></p> </blockquote> <p>So, you would prepare this solution by adding enough water to your <mathjax>#"160-mL"#</mathjax> sample of <mathjax>#"0.25-M"#</mathjax> hydrochloric acid solution to make the total volume of the resulting solution equal to <mathjax>#"1.00 L"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/231174" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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3,419	aa7ded7a-6ddd-11ea-8079-ccda262736ce	https://socratic.org/questions/what-is-the-volume-in-liters-of-5-0-mol-of-ne-gas-at-stp	22.41 liters	start physical_unit 10 11 volume l qc_end physical_unit 10 11 7 8 mole qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] Ne gas [IN] liters"}]	[{"type":"physical unit","value":"22.41 liters"}]	[{"type":"physical unit","value":"Mole [OF] Ne gas [=] \\pu{5.0 mol}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume, in liters, of 5.0 mol of Ne gas at STP? </h1>	null	22.41 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"We use the ideal gas law,"#</mathjax></p> <p><mathjax>#color(orange)(PV=nRT)#</mathjax></p> <p><mathjax>#"We know the conditions for STP are the following,"#</mathjax></p> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax></p> <p><mathjax>#V=?#</mathjax></p> <p><mathjax>#n = 1.0#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#R=8.314#</mathjax></p> <p><mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> <p>Plug in your values.</p> <p><mathjax>#color(orange)(V_(Ne)=(nRT)/(P)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=(2270.9691)/(101.325)#</mathjax></p> <p><mathjax>#V_(Ne)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.41#</mathjax> <mathjax>#L#</mathjax></p> <p><mathjax>#"This is true because the volume of an ideal gas is 22.41 L/mol at STP."#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_(Ne)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.41#</mathjax> <mathjax>#L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"We use the ideal gas law,"#</mathjax></p> <p><mathjax>#color(orange)(PV=nRT)#</mathjax></p> <p><mathjax>#"We know the conditions for STP are the following,"#</mathjax></p> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax></p> <p><mathjax>#V=?#</mathjax></p> <p><mathjax>#n = 1.0#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#R=8.314#</mathjax></p> <p><mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> <p>Plug in your values.</p> <p><mathjax>#color(orange)(V_(Ne)=(nRT)/(P)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=(2270.9691)/(101.325)#</mathjax></p> <p><mathjax>#V_(Ne)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.41#</mathjax> <mathjax>#L#</mathjax></p> <p><mathjax>#"This is true because the volume of an ideal gas is 22.41 L/mol at STP."#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume, in liters, of 5.0 mol of Ne gas at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="580648" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/elsie-1"><img alt="" class="" src="https://profilepictures.socratic.org/XIuka66NTaKzujOt57Ou_Colorful%20Sky.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/elsie-1"> elsie ☆ </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-24T00:24:17" itemprop="dateCreated"> Mar 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_(Ne)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.41#</mathjax> <mathjax>#L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"We use the ideal gas law,"#</mathjax></p> <p><mathjax>#color(orange)(PV=nRT)#</mathjax></p> <p><mathjax>#"We know the conditions for STP are the following,"#</mathjax></p> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax></p> <p><mathjax>#V=?#</mathjax></p> <p><mathjax>#n = 1.0#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#R=8.314#</mathjax></p> <p><mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> <p>Plug in your values.</p> <p><mathjax>#color(orange)(V_(Ne)=(nRT)/(P)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=((1.0mol)(8.314)(273.15))/(101.325)#</mathjax></p> <p><mathjax>#=(2270.9691)/(101.325)#</mathjax></p> <p><mathjax>#V_(Ne)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.41#</mathjax> <mathjax>#L#</mathjax></p> <p><mathjax>#"This is true because the volume of an ideal gas is 22.41 L/mol at STP."#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/580648" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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3,420	ad212ad1-6ddd-11ea-a32f-ccda262736ce	https://socratic.org/questions/if-200-grams-of-water-is-to-be-heated-from-24-c-to-100-c-to-make-a-cup-of-tea-ho	63.54 kJ	start physical_unit 4 4 heat_energy kj qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 4 4 10 11 temperature qc_end physical_unit 4 4 13 14 temperature qc_end physical_unit 4 4 33 36 specific_heat qc_end end	[{"type":"physical unit","value":"Added heat [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"63.54 kJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{200 grams}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{24 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Specific heat [OF] water [=] \\pu{4.18 J/(g * ℃)}"}]	<h1 class="questionTitle" itemprop="name">If 200 grams of water is to be heated from 24°C to 100°C to make a cup of tea, how much heat must be added? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of water is 4.18 <mathjax>#J#</mathjax><mathjax>#/#</mathjax><mathjax>#g*C#</mathjax>.</p></div> </h2> </div> </div>	63.54 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, a substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that sample by <mathjax>#1^@"C"#</mathjax>. </p> <p>In water's case, you know that its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> is equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax>. This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>, you need to supply <mathjax>#"4.18 J"#</mathjax> of heat. </p> <p>How much heat would you need to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>? </p> <p>Well, if you need <mathjax>#"4.18 J"#</mathjax> <strong>per</strong> gram to increase its temperature by <mathjax>#1^@"C"#</mathjax>, it follows that you will need <mathjax>#200#</mathjax> <strong>times more heat</strong> to get this done. </p> <p>Likewise, if you were to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>, you'd need <mathjax>#76#</mathjax> <strong>times more heat</strong> than when increasing the temperature of <mathjax>#"1 g"#</mathjax> by <mathjax>#1^@"C"#</mathjax>. </p> <p>Combine these two requirements and you get the total amount of heat required to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>.</p> <p>Mathematically, this is expressed using the following equation</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed/lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#q = 200 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (100 - 24)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "63536 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("64 kJ")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = "64 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, a substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that sample by <mathjax>#1^@"C"#</mathjax>. </p> <p>In water's case, you know that its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> is equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax>. This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>, you need to supply <mathjax>#"4.18 J"#</mathjax> of heat. </p> <p>How much heat would you need to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>? </p> <p>Well, if you need <mathjax>#"4.18 J"#</mathjax> <strong>per</strong> gram to increase its temperature by <mathjax>#1^@"C"#</mathjax>, it follows that you will need <mathjax>#200#</mathjax> <strong>times more heat</strong> to get this done. </p> <p>Likewise, if you were to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>, you'd need <mathjax>#76#</mathjax> <strong>times more heat</strong> than when increasing the temperature of <mathjax>#"1 g"#</mathjax> by <mathjax>#1^@"C"#</mathjax>. </p> <p>Combine these two requirements and you get the total amount of heat required to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>.</p> <p>Mathematically, this is expressed using the following equation</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed/lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#q = 200 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (100 - 24)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "63536 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("64 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 200 grams of water is to be heated from 24°C to 100°C to make a cup of tea, how much heat must be added? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of water is 4.18 <mathjax>#J#</mathjax><mathjax>#/#</mathjax><mathjax>#gC#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202606" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-23T15:40:42" itemprop="dateCreated"> Dec 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = "64 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, a substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that sample by <mathjax>#1^@"C"#</mathjax>. </p> <p>In water's case, you know that its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> is equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax>. This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>, you need to supply <mathjax>#"4.18 J"#</mathjax> of heat. </p> <p>How much heat would you need to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>? </p> <p>Well, if you need <mathjax>#"4.18 J"#</mathjax> <strong>per</strong> gram to increase its temperature by <mathjax>#1^@"C"#</mathjax>, it follows that you will need <mathjax>#200#</mathjax> <strong>times more heat</strong> to get this done. </p> <p>Likewise, if you were to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>, you'd need <mathjax>#76#</mathjax> <strong>times more heat</strong> than when increasing the temperature of <mathjax>#"1 g"#</mathjax> by <mathjax>#1^@"C"#</mathjax>. </p> <p>Combine these two requirements and you get the total amount of heat required to increase the temperature of <mathjax>#"200 g"#</mathjax> of water by <mathjax>#76^@"C"#</mathjax>.</p> <p>Mathematically, this is expressed using the following equation</p> <blockquote> <p><mathjax>#color(blue)(q = m c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed/lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#q = 200 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (100 - 24)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "63536 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("64 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202606" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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The specific heat of water is 4.18 #J##/##g*C#.
3,421	ab67fca8-6ddd-11ea-982c-ccda262736ce	https://socratic.org/questions/68-ml-of-a-0-28-m-cacl2-solution-is-added-to-92-ml-of-a-0-46-m-cacl2-solution-de	0.38 M	start physical_unit 23 25 concentration mol/l qc_end physical_unit 6 7 4 5 concentration qc_end physical_unit 6 7 0 1 volume qc_end physical_unit 6 7 15 16 concentration qc_end physical_unit 6 7 11 12 volume qc_end end	[{"type":"physical unit","value":"Concentration [OF] the combined solution [IN] M"}]	[{"type":"physical unit","value":"0.38 M"}]	[{"type":"physical unit","value":"Volume1 [OF] CaCl2 solution [=] \\pu{68 mL}"},{"type":"physical unit","value":"Molarity1 [OF] CaCl2 solution [=] \\pu{0.28 M}"},{"type":"physical unit","value":"Volume2 [OF] CaCl2 solution [=] \\pu{92 mL}"},{"type":"physical unit","value":"Molarity2 [OF] CaCl2 solution [=] \\pu{0.46 M}"}]	<h1 class="questionTitle" itemprop="name">68 mL of a 0.28 M CaCl2 solution is added to 92 mL of a 0.46 M CaCl2 solution. Determine the concentration of the combined solution. Show all work with units. How would you solve this?</h1>	null	0.38 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The basic definition of concentration is as <em>amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per unit volume.</em> That is..........</p> <p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Most of the time we want to assess <mathjax>#"moles of solute"#</mathjax>, and this is simply the product:</p> <p><mathjax>#"Moles of solute"="Volume"xx"concentration"#</mathjax>. I would get familiar with this expression, because you will use it a lot.</p> <p>.........And in problems like these we must assume (REASONABLY!) that the volumes are additive. And so to address your problem (finally!), we solve the quotient:</p> <p><mathjax>#(0.092Lxx0.46molL^-1+0.068Lxx0.28molL^-1)/((92+68)xx10^-3L)#</mathjax></p> <p><mathjax>#~=0.4molL^-1#</mathjax></p> <p>Do the units in the quotient cancel to give an answer in <mathjax>#molL^-1#</mathjax>? It is your problem not mine. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I hope I would solve it correctly.</p> <p>......I finally get a concentration with respect to <mathjax>#CaCl_2#</mathjax> of <mathjax>#~=0.4molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The basic definition of concentration is as <em>amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per unit volume.</em> That is..........</p> <p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Most of the time we want to assess <mathjax>#"moles of solute"#</mathjax>, and this is simply the product:</p> <p><mathjax>#"Moles of solute"="Volume"xx"concentration"#</mathjax>. I would get familiar with this expression, because you will use it a lot.</p> <p>.........And in problems like these we must assume (REASONABLY!) that the volumes are additive. And so to address your problem (finally!), we solve the quotient:</p> <p><mathjax>#(0.092Lxx0.46molL^-1+0.068Lxx0.28molL^-1)/((92+68)xx10^-3L)#</mathjax></p> <p><mathjax>#~=0.4molL^-1#</mathjax></p> <p>Do the units in the quotient cancel to give an answer in <mathjax>#molL^-1#</mathjax>? It is your problem not mine. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">68 mL of a 0.28 M CaCl2 solution is added to 92 mL of a 0.46 M CaCl2 solution. Determine the concentration of the combined solution. Show all work with units. How would you solve this?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="419441" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-08T03:35:05" itemprop="dateCreated"> May 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I hope I would solve it correctly.</p> <p>......I finally get a concentration with respect to <mathjax>#CaCl_2#</mathjax> of <mathjax>#~=0.4molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The basic definition of concentration is as <em>amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per unit volume.</em> That is..........</p> <p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Most of the time we want to assess <mathjax>#"moles of solute"#</mathjax>, and this is simply the product:</p> <p><mathjax>#"Moles of solute"="Volume"xx"concentration"#</mathjax>. I would get familiar with this expression, because you will use it a lot.</p> <p>.........And in problems like these we must assume (REASONABLY!) that the volumes are additive. And so to address your problem (finally!), we solve the quotient:</p> <p><mathjax>#(0.092Lxx0.46molL^-1+0.068Lxx0.28molL^-1)/((92+68)xx10^-3L)#</mathjax></p> <p><mathjax>#~=0.4molL^-1#</mathjax></p> <p>Do the units in the quotient cancel to give an answer in <mathjax>#molL^-1#</mathjax>? It is your problem not mine. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419441" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="419868" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-08T21:22:39" itemprop="dateCreated"> May 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of the combined solution is 0.38 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The steps to follow are:</p> <ol> <li>Calculate the number of moles in each solution.</li> <li>Use the total moles and the total volume to calculate the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the combined solution.</li> </ol> <blockquote></blockquote> <p><strong>1. Number of moles in each solution</strong></p> <p><strong>(a)</strong> Solution 1</p> <p><mathjax>#"Moles of CaCl"_2 = 0.068 color(red)(cancel(color(black)("L solution"))) × ("0.28 mol CaCl"_2)/(1 color(red)(cancel(color(black)("L solution")))) = "0.0190 mol CaCl"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(b)</strong> Solution2</p> <p><mathjax>#"Moles of CaCl"_2 = 0.092 color(red)(cancel(color(black)("L solution"))) × ("0.46 mol CaCl"_2)/(1 color(red)(cancel(color(black)("L solution")))) = "0.0423 mol CaCl"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Molarity of combined <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a></strong></p> <p><mathjax>#"Total moles" = "(0.0190 + 0.0423) mol" = "0.0613 mol"#</mathjax></p> <p><mathjax>#"Total volume" = "(68 + 92) mL" = "160 mL" = "0.160 L"#</mathjax></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.0613 mol"/"0.160 L" = "0.38 mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419868" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8368 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	68 mL of a 0.28 M CaCl2 solution is added to 92 mL of a 0.46 M CaCl2 solution. Determine the concentration of the combined solution. Show all work with units. How would you solve this?	null
3,422	a867d7e4-6ddd-11ea-967d-ccda262736ce	https://socratic.org/questions/5728e8567c014907a713414e	Mg(NO3)2(s) + n H2O -> Mg^2+(aq) + 2 NO3-(aq)	start chemical_equation qc_end substance 8 9 qc_end substance 11 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the dissolution"}]	[{"type":"chemical equation","value":"Mg(NO3)2(s) + n H2O -> Mg^2+(aq) + 2 NO3-(aq)"}]	[{"type":"substance name","value":"magnesium nitrate"},{"type":"substance name","value":"water"}]	<h1 class="questionTitle" itemprop="name">What is the reaction for the dissolution of magnesium nitrate in water?</h1>	null	Mg(NO3)2(s) + n H2O -> Mg^2+(aq) + 2 NO3-(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Many would classify the reaction depicted above as a physical reaction rather than a chemical one. And if you review the history of this thread in a few hours, you will probably see certain people making precisely that objection. </p> <p>The reaction above is, nevertheless, a chemical reaction, in that we have taken solid magnesium nitrate, an ionic solid, and dissolved it in water to form aquated ions. We write <mathjax>#Mg^(2+)(aq)#</mathjax>; what this represents is <mathjax>#[Mg(OH_2)_6]^(2+)#</mathjax>, a coordination complex, if you like, of <mathjax>#Mg^(2+)#</mathjax>. The nitrate anions are similarly aquated.</p> <p>Chemical change is characterized by the formation of new substances and the making and breaking of strong chemical bonds. These are precisely what have happened in the chemical reaction depicted. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(NO_3)_2(s) + nH_2O rarr Mg^(2+)(aq) + 2NO_3^(-)(aq)#</mathjax></p> <p><mathjax>#Mg^(2+)(aq) = [Mg(OH_2)_6]^(2+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Many would classify the reaction depicted above as a physical reaction rather than a chemical one. And if you review the history of this thread in a few hours, you will probably see certain people making precisely that objection. </p> <p>The reaction above is, nevertheless, a chemical reaction, in that we have taken solid magnesium nitrate, an ionic solid, and dissolved it in water to form aquated ions. We write <mathjax>#Mg^(2+)(aq)#</mathjax>; what this represents is <mathjax>#[Mg(OH_2)_6]^(2+)#</mathjax>, a coordination complex, if you like, of <mathjax>#Mg^(2+)#</mathjax>. The nitrate anions are similarly aquated.</p> <p>Chemical change is characterized by the formation of new substances and the making and breaking of strong chemical bonds. These are precisely what have happened in the chemical reaction depicted. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the reaction for the dissolution of magnesium nitrate in water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263865" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-09T09:04:54" itemprop="dateCreated"> May 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(NO_3)_2(s) + nH_2O rarr Mg^(2+)(aq) + 2NO_3^(-)(aq)#</mathjax></p> <p><mathjax>#Mg^(2+)(aq) = [Mg(OH_2)_6]^(2+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Many would classify the reaction depicted above as a physical reaction rather than a chemical one. And if you review the history of this thread in a few hours, you will probably see certain people making precisely that objection. </p> <p>The reaction above is, nevertheless, a chemical reaction, in that we have taken solid magnesium nitrate, an ionic solid, and dissolved it in water to form aquated ions. We write <mathjax>#Mg^(2+)(aq)#</mathjax>; what this represents is <mathjax>#[Mg(OH_2)_6]^(2+)#</mathjax>, a coordination complex, if you like, of <mathjax>#Mg^(2+)#</mathjax>. The nitrate anions are similarly aquated.</p> <p>Chemical change is characterized by the formation of new substances and the making and breaking of strong chemical bonds. These are precisely what have happened in the chemical reaction depicted. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263865" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16923 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the reaction for the dissolution of magnesium nitrate in water?	null
3,423	acd557c4-6ddd-11ea-ae86-ccda262736ce	https://socratic.org/questions/how-would-you-balance-na-h2o-naoh-h2-1	Na + H2O -> NaOH + 1/2 H2	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Na + H2O -> NaOH + 1/2 H2"}]	[{"type":"chemical equation","value":"Na + H2O -> NaOH + H2"}]	<h1 class="questionTitle" itemprop="name">How would you balance Na+H2O --> NaOH + H2? </h1>	null	Na + H2O -> NaOH + 1/2 H2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium is oxidized; hydrogen is reduced. You can double the equation if you like to remove the 1/2 coefficient, but the equation is stoichiometrically balanced. </p> <p>What does <em>stoichiometric</em> mean?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium is oxidized; hydrogen is reduced. You can double the equation if you like to remove the 1/2 coefficient, but the equation is stoichiometrically balanced. </p> <p>What does <em>stoichiometric</em> mean?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance Na+H2O --> NaOH + H2? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="207522" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-03T13:18:42" itemprop="dateCreated"> Jan 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium is oxidized; hydrogen is reduced. You can double the equation if you like to remove the 1/2 coefficient, but the equation is stoichiometrically balanced. </p> <p>What does <em>stoichiometric</em> mean?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/207522" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2453 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance Na+H2O --> NaOH + H2?	null
3,424	a8d51148-6ddd-11ea-8691-ccda262736ce	https://socratic.org/questions/586bedfeb72cff43cc08d135	OH- + H3O+ -> 2 H2O	start chemical_equation qc_end substance 10 11 qc_end substance 13 14 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"OH- + H3O+ -> 2 H2O"}]	[{"type":"substance name","value":"Potassium hydroxide"},{"type":"substance name","value":"Hydrochloric acid"}]	<h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction between potassium hydroxide and hydrochloric acid?</h1>	null	OH- + H3O+ -> 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is simplicity itself: hydronium ion reacts with hydroxide ion to give water.</p> <p>Of course the complete equation is:</p> <p><mathjax>#HCl(aq) + KOH(aq) rarr H_2O(l) + KCl(aq)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HO^(-) + H_3O^(+) rarr 2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is simplicity itself: hydronium ion reacts with hydroxide ion to give water.</p> <p>Of course the complete equation is:</p> <p><mathjax>#HCl(aq) + KOH(aq) rarr H_2O(l) + KCl(aq)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction between potassium hydroxide and hydrochloric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="359862" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-03T18:58:27" itemprop="dateCreated"> Jan 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HO^(-) + H_3O^(+) rarr 2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is simplicity itself: hydronium ion reacts with hydroxide ion to give water.</p> <p>Of course the complete equation is:</p> <p><mathjax>#HCl(aq) + KOH(aq) rarr H_2O(l) + KCl(aq)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/359862" itemprop="url">Answer link</a> </div> </div> </div> </div> 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3,425	abf9a66c-6ddd-11ea-aeb4-ccda262736ce	https://socratic.org/questions/what-is-the-dissociation-of-zn-oh-2	Zn(OH)2 <=> Zn^2+ + 2 OH-	start chemical_equation qc_end chemical_equation 5 5 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the dissociation"}]	[{"type":"chemical equation","value":"Zn(OH)2 <=> Zn^2+ + 2 OH-"}]	[{"type":"chemical equation","value":"Zn(OH)2"}]	<h1 class="questionTitle" itemprop="name">What is the dissociation of #"Zn"("OH")_2#? </h1>	null	Zn(OH)2 <=> Zn^2+ + 2 OH-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Zinc hydroxide is considered <strong>insoluble</strong> in water, so right from the start, you know that you're dealing with a <strong>solubility equilibrium</strong> between the undissociated solid and the solvated ions. </p> <p>Now, <strong>each mole</strong> of zinc hydroxide contains</p> <blockquote> <ul> <li><em><strong>one mole</strong> of zinc cations</em>, <mathjax>#1 xx "Zn"^(2+)#</mathjax></li> <li><em><strong>two moles</strong> of hydroxide anions</em>, <mathjax>#2 xx "OH"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that when you dissolve solid zinc hydroxide in water, the following equilibrium will be established</p> <blockquote> <p><mathjax>#"Zn"("OH")_ (2(s)) rightleftharpoons "Zn"_ ((aq))^(2+) + 2"OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This equilibrium will lie <strong>to the left</strong>, meaning that only very small quantities of solid zinc hydroxide will dissociate in aqueous solution to produce zinc cations and hydroxide anions.</p> <p>The <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, which is essentially a measure of the degree of dissociation of zinc hydroxide in water, is equal to <mathjax>#3.0 * 10^(-16)#</mathjax> at room temperature. </p> <p><a href="https://en.wikipedia.org/wiki/Zinc_hydroxide" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Zinc_hydroxide</a></p> <p>This basically tells you that the electrostatic attraction that exists between the zinc cations and the hydroxide anions <em>far exceeds</em> the attraction between the polar water molecules and the two ions <mathjax>#->#</mathjax> zinc hydroxide is considered <em>insoluble</em> in aqueous solution.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Zn"("OH")_ (2(s)) rightleftharpoons "Zn"_ ((aq))^(2+) + 2"OH"_ ((aq))^(-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Zinc hydroxide is considered <strong>insoluble</strong> in water, so right from the start, you know that you're dealing with a <strong>solubility equilibrium</strong> between the undissociated solid and the solvated ions. </p> <p>Now, <strong>each mole</strong> of zinc hydroxide contains</p> <blockquote> <ul> <li><em><strong>one mole</strong> of zinc cations</em>, <mathjax>#1 xx "Zn"^(2+)#</mathjax></li> <li><em><strong>two moles</strong> of hydroxide anions</em>, <mathjax>#2 xx "OH"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that when you dissolve solid zinc hydroxide in water, the following equilibrium will be established</p> <blockquote> <p><mathjax>#"Zn"("OH")_ (2(s)) rightleftharpoons "Zn"_ ((aq))^(2+) + 2"OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This equilibrium will lie <strong>to the left</strong>, meaning that only very small quantities of solid zinc hydroxide will dissociate in aqueous solution to produce zinc cations and hydroxide anions.</p> <p>The <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, which is essentially a measure of the degree of dissociation of zinc hydroxide in water, is equal to <mathjax>#3.0 * 10^(-16)#</mathjax> at room temperature. </p> <p><a href="https://en.wikipedia.org/wiki/Zinc_hydroxide" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Zinc_hydroxide</a></p> <p>This basically tells you that the electrostatic attraction that exists between the zinc cations and the hydroxide anions <em>far exceeds</em> the attraction between the polar water molecules and the two ions <mathjax>#->#</mathjax> zinc hydroxide is considered <em>insoluble</em> in aqueous solution.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the dissociation of #"Zn"("OH")_2#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="444751" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-27T00:45:41" itemprop="dateCreated"> Jun 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Zn"("OH")_ (2(s)) rightleftharpoons "Zn"_ ((aq))^(2+) + 2"OH"_ ((aq))^(-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Zinc hydroxide is considered <strong>insoluble</strong> in water, so right from the start, you know that you're dealing with a <strong>solubility equilibrium</strong> between the undissociated solid and the solvated ions. </p> <p>Now, <strong>each mole</strong> of zinc hydroxide contains</p> <blockquote> <ul> <li><em><strong>one mole</strong> of zinc cations</em>, <mathjax>#1 xx "Zn"^(2+)#</mathjax></li> <li><em><strong>two moles</strong> of hydroxide anions</em>, <mathjax>#2 xx "OH"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that when you dissolve solid zinc hydroxide in water, the following equilibrium will be established</p> <blockquote> <p><mathjax>#"Zn"("OH")_ (2(s)) rightleftharpoons "Zn"_ ((aq))^(2+) + 2"OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This equilibrium will lie <strong>to the left</strong>, meaning that only very small quantities of solid zinc hydroxide will dissociate in aqueous solution to produce zinc cations and hydroxide anions.</p> <p>The <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, which is essentially a measure of the degree of dissociation of zinc hydroxide in water, is equal to <mathjax>#3.0 * 10^(-16)#</mathjax> at room temperature. </p> <p><a href="https://en.wikipedia.org/wiki/Zinc_hydroxide" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Zinc_hydroxide</a></p> <p>This basically tells you that the electrostatic attraction that exists between the zinc cations and the hydroxide anions <em>far exceeds</em> the attraction between the polar water molecules and the two ions <mathjax>#->#</mathjax> zinc hydroxide is considered <em>insoluble</em> in aqueous solution.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/444751" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? 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3,426	a8467a0c-6ddd-11ea-b223-ccda262736ce	https://socratic.org/questions/562e2dc311ef6b14208006d0	MgO + H2O -> Mg(OH)2	start chemical_equation qc_end substance 8 8 qc_end substance 5 5 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"MgO + H2O -> Mg(OH)2"}]	[{"type":"substance name","value":"Water"},{"type":"substance name","value":"Magnesium oxid"},{"type":"substance name","value":"Calcium"}]	<h1 class="questionTitle" itemprop="name">How would magnesium oxide, and calcium react with water?</h1>	null	MgO + H2O -> Mg(OH)2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have an idea that magnesium oxide would only be sparingly soluble in water. Both the oxide and its hydroxide would be fairly insoluble. </p> <p><mathjax>#CaO#</mathjax>, which features the much large <mathjax>#Ca^(2+)#</mathjax> ion, would react quantitatively, and would spit when you added water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgO + H_2O rarr Mg(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have an idea that magnesium oxide would only be sparingly soluble in water. Both the oxide and its hydroxide would be fairly insoluble. </p> <p><mathjax>#CaO#</mathjax>, which features the much large <mathjax>#Ca^(2+)#</mathjax> ion, would react quantitatively, and would spit when you added water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would magnesium oxide, and calcium react with water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208852" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-06T08:52:33" itemprop="dateCreated"> Jan 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgO + H_2O rarr Mg(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have an idea that magnesium oxide would only be sparingly soluble in water. Both the oxide and its hydroxide would be fairly insoluble. </p> <p><mathjax>#CaO#</mathjax>, which features the much large <mathjax>#Ca^(2+)#</mathjax> ion, would react quantitatively, and would spit when you added water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208852" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4155 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would magnesium oxide, and calcium react with water?	null
3,427	aa943f06-6ddd-11ea-8285-ccda262736ce	https://socratic.org/questions/how-do-you-write-the-balanced-chemical-equation-for-the-acid-hydrolysis-of-methy	C3H7COOCH3 + H2O/H+ -> C3H7COOH + CH3OH	start chemical_equation qc_end substance 13 14 qc_end end	[{"type":"other","value":"Chemical Equation [OF] acid hydrolysis"}]	[{"type":"chemical equation","value":"C3H7COOCH3 + H2O/H+ -> C3H7COOH + CH3OH"}]	[{"type":"substance name","value":"Methyl butanoate"}]	<h1 class="questionTitle" itemprop="name">How do you write the balanced chemical equation for the acid hydrolysis of methyl butanoate?</h1>	null	C3H7COOCH3 + H2O/H+ -> C3H7COOH + CH3OH	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we talk about the acid hydrolysis of an ester, we really mean just adding water to that ester (using an acid catalyst) and breaking the ester bond (<mathjax>#"COO"#</mathjax>) to form an alcohol and a carboxylic acid. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_7"COOCH"_3 + "H"_2"O/H"^+ rarr "C"_3"H"_7"COOH" + "CH"_3"OH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we talk about the acid hydrolysis of an ester, we really mean just adding water to that ester (using an acid catalyst) and breaking the ester bond (<mathjax>#"COO"#</mathjax>) to form an alcohol and a carboxylic acid. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write the balanced chemical equation for the acid hydrolysis of methyl butanoate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="354208" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-19T17:44:16" itemprop="dateCreated"> Dec 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_7"COOCH"_3 + "H"_2"O/H"^+ rarr "C"_3"H"_7"COOH" + "CH"_3"OH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we talk about the acid hydrolysis of an ester, we really mean just adding water to that ester (using an acid catalyst) and breaking the ester bond (<mathjax>#"COO"#</mathjax>) to form an alcohol and a carboxylic acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/354208" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11332 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write the balanced chemical equation for the acid hydrolysis of methyl butanoate?	null
3,428	a8b2e5ba-6ddd-11ea-97de-ccda262736ce	https://socratic.org/questions/you-have-a-vinegar-solution-you-believe-to-be-0-83-m-you-are-going-to-titrate-20	32 mL	start physical_unit 22 23 volume ml qc_end physical_unit 3 4 9 10 molarity qc_end physical_unit 3 4 16 17 volume qc_end physical_unit 22 23 29 30 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] NaOH solution [IN] mL"}]	[{"type":"physical unit","value":"32 mL"}]	[{"type":"physical unit","value":"Molarity [OF] vinegar solution [=] \\pu{0.83 M}"},{"type":"physical unit","value":"Volume [OF] vinegar solution [=] \\pu{20.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.519 M}"}]	<h1 class="questionTitle" itemprop="name">You have a vinegar solution you believe to be 0.83 M. You are going to titrate 20.0mL of it with a NaOH solution that you know to be 0.519 M. At what volume of added NaOH solution would you expect to see the end point? </h1>	null	32 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's write the formula for acetic acid as <mathjax>#"HA"#</mathjax>.</p> <p>Then the equation for the reaction is</p> <p><mathjax>#"HA + NaOH" → "NaA" + "H"_2"O"#</mathjax>.</p> <blockquote></blockquote> <p><strong>1.</strong> Calculate the moles of <mathjax>#"HA"#</mathjax></p> <p><mathjax>#"Moles of HA" = 0.0200 color(red)(cancel(color(black)("L HA"))) ×( "0.83 mol HA")/(1 color(red)(cancel(color(black)("L HA")))) = "0.0166 mol HA"#</mathjax></p> <blockquote></blockquote> <p><strong>2.</strong> Calculate the moles of <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Moles of NaOH" = 0.0166 color(red)(cancel(color(black)("mol HA"))) × ("1 mol NaOH")/(1 color(red)(cancel(color(black)("mol HA")))) = "0.0166 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>3.</strong> Calculate the volume of the <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Volume of NaOH" = 0.0166 color(red)(cancel(color(black)("mol NaOH"))) × ("1 L NaOH")/(0.519 color(red)(cancel(color(black)("mol NaOH")))) = "0.032 L" = "32 mL"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You should expect to see the endpoint at 32 mL of added <mathjax>#"NaOH"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's write the formula for acetic acid as <mathjax>#"HA"#</mathjax>.</p> <p>Then the equation for the reaction is</p> <p><mathjax>#"HA + NaOH" → "NaA" + "H"_2"O"#</mathjax>.</p> <blockquote></blockquote> <p><strong>1.</strong> Calculate the moles of <mathjax>#"HA"#</mathjax></p> <p><mathjax>#"Moles of HA" = 0.0200 color(red)(cancel(color(black)("L HA"))) ×( "0.83 mol HA")/(1 color(red)(cancel(color(black)("L HA")))) = "0.0166 mol HA"#</mathjax></p> <blockquote></blockquote> <p><strong>2.</strong> Calculate the moles of <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Moles of NaOH" = 0.0166 color(red)(cancel(color(black)("mol HA"))) × ("1 mol NaOH")/(1 color(red)(cancel(color(black)("mol HA")))) = "0.0166 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>3.</strong> Calculate the volume of the <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Volume of NaOH" = 0.0166 color(red)(cancel(color(black)("mol NaOH"))) × ("1 L NaOH")/(0.519 color(red)(cancel(color(black)("mol NaOH")))) = "0.032 L" = "32 mL"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You have a vinegar solution you believe to be 0.83 M. You are going to titrate 20.0mL of it with a NaOH solution that you know to be 0.519 M. At what volume of added NaOH solution would you expect to see the end point? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419954" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-08T23:47:14" itemprop="dateCreated"> May 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You should expect to see the endpoint at 32 mL of added <mathjax>#"NaOH"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's write the formula for acetic acid as <mathjax>#"HA"#</mathjax>.</p> <p>Then the equation for the reaction is</p> <p><mathjax>#"HA + NaOH" → "NaA" + "H"_2"O"#</mathjax>.</p> <blockquote></blockquote> <p><strong>1.</strong> Calculate the moles of <mathjax>#"HA"#</mathjax></p> <p><mathjax>#"Moles of HA" = 0.0200 color(red)(cancel(color(black)("L HA"))) ×( "0.83 mol HA")/(1 color(red)(cancel(color(black)("L HA")))) = "0.0166 mol HA"#</mathjax></p> <blockquote></blockquote> <p><strong>2.</strong> Calculate the moles of <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Moles of NaOH" = 0.0166 color(red)(cancel(color(black)("mol HA"))) × ("1 mol NaOH")/(1 color(red)(cancel(color(black)("mol HA")))) = "0.0166 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>3.</strong> Calculate the volume of the <mathjax>#"NaOH"#</mathjax></p> <p><mathjax>#"Volume of NaOH" = 0.0166 color(red)(cancel(color(black)("mol NaOH"))) × ("1 L NaOH")/(0.519 color(red)(cancel(color(black)("mol NaOH")))) = "0.032 L" = "32 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419954" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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You are going to titrate 20.0mL of it with a NaOH solution that you know to be 0.519 M. At what volume of added NaOH solution would you expect to see the end point?	null
3,429	aaf63046-6ddd-11ea-b346-ccda262736ce	https://socratic.org/questions/how-many-moles-of-kno-3-are-contained-in-one-liter-of-0-2-kno-3-solution	0.20 moles	start physical_unit 4 4 mole mol qc_end physical_unit 13 14 11 12 molarity qc_end physical_unit 13 14 8 9 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] KNO3 [IN] moles"}]	[{"type":"physical unit","value":"0.20 moles"}]	[{"type":"physical unit","value":"Molarity [OF] KNO3 solution [=] \\pu{0.2 M}"},{"type":"physical unit","value":"Volume [OF] KNO3 solution [=] \\pu{1 liter}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #KNO_3# are contained in one liter of 0,2 #KNO_3# solution?</h1>	null	0.20 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>Here, we apparently have a <mathjax>#1L#</mathjax> volume of <mathjax>#0.2molL^-1#</mathjax> concentration....</p> <p>And thus to get the molar quantity, we take the product.....</p> <p><mathjax>#"molarity"xx"volume of solution"=1cancelLxx0.2molcancel(L^-1)=0.2mol#</mathjax>...</p> <p>i.e. a mass of <mathjax>#0.2molxx101.1gmol^-1=20.2*g#</mathjax> with respect to potassium nitrate...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I think there is a <mathjax>#0.2#</mathjax> molar quantity...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>Here, we apparently have a <mathjax>#1L#</mathjax> volume of <mathjax>#0.2molL^-1#</mathjax> concentration....</p> <p>And thus to get the molar quantity, we take the product.....</p> <p><mathjax>#"molarity"xx"volume of solution"=1cancelLxx0.2molcancel(L^-1)=0.2mol#</mathjax>...</p> <p>i.e. a mass of <mathjax>#0.2molxx101.1gmol^-1=20.2*g#</mathjax> with respect to potassium nitrate...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #KNO_3# are contained in one liter of 0,2 #KNO_3# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="513984" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-30T19:41:08" itemprop="dateCreated"> Nov 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I think there is a <mathjax>#0.2#</mathjax> molar quantity...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>Here, we apparently have a <mathjax>#1L#</mathjax> volume of <mathjax>#0.2molL^-1#</mathjax> concentration....</p> <p>And thus to get the molar quantity, we take the product.....</p> <p><mathjax>#"molarity"xx"volume of solution"=1cancelLxx0.2molcancel(L^-1)=0.2mol#</mathjax>...</p> <p>i.e. a mass of <mathjax>#0.2molxx101.1gmol^-1=20.2*g#</mathjax> with respect to potassium nitrate...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/513984" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> 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